Answer:
The area of the rectangular deck is 36 sq feet.
Step-by-step explanation:
Let the width of the deck = k ft
So, the length of the deck = (4k) ft
Now, perimeter = 30 ft
PERIMETER OF A RECTANGLE = 2(LENGTH + WIDTH)
⇒2( k + 4k) = 30
or, 2 x 5k = 30 ⇒ 10k = 30
⇒ k = 30/10 = 3
So, the width of the deck = k = 3 ft
Length of the deck = 4k = 3 x 4 = 12 ft
Now, AREA OF A RECTANGLE = LENGTH X WIDTH
So, the area of the rectangular deck = 3 ft x 12 ft
= 36 sq feet
Hence, the area of the rectangular deck is 36 sq feet.
Answer: the diagonal is 10 units
Step-by-step explanation:
The rectangle has 2 parallel and equal sides. Each of the 4 angles in a rectangle is 90°. Therefore, the diagonal of the rectangle divides it into 2 equal right angle triangles and the diagonal represents the hypotenuse of both right triangles.
To determine the length of the diagonal of the rectangle, d, , we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
Therefore
d² = 5² + (5√3)²
d² = 25 + 25×3 = 100
d = √100
d = 10 units
Answer:
x=5.5
Step-by-step explanation:
We can solve this equation by using the various properties and PEMDAS.
First, we would want to subtract 18 on both sides, to even out the equation.
The result is -7x=-38.5
Now we can isolate the x by dividing both sides by -7.
-38/-7=5.5
Thus, x=5.5
Hope this helps!
P = 5 .............................................
this is how=
first you expand the second equation
<span>25 + 4p = -18 + -12 + 6p + 9p
</span>
then you add the like terms in the second equation:
25 + 4p = -30 + 15p
then this is how=
25+30 = 15p -4p
55=11p
p= 5
