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skad [1K]
3 years ago
9

I need help with 2 questions in distributive property

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

i don't know

Step-by-step explanation:

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Collins has a part-time job as a dog walker. The table below shows the amount of money Collins earned for different numbers of h
kondor19780726 [428]

Answer:

See below.

Step-by-step explanation:

Part A:

For Dog walking, he earns $30 for 5 hours of work.

He earns $36 for 6 hours of work.

$30/5 hours = $6/hour

$36/6 hours = $6/hour

He earns $6/hour dog walking.

For 8 hours, he earns 8 hours * $6/hour = $48

To earn $66, he works 66/6 = 11 hours.

5 30

6 36

8 48

11 66

Part B:

He earns $7/hour for yard work, so multiply the number of hours by 7 to find the money he earns.

Table for yard work

Hours     Money

5             $35

6             $42

8             $56

Part C:

For 5 hours, he earns $35 for yard work and $30 as a dog walker.

$35 - $30 = $5

3 0
3 years ago
The aquarium has 3 more yellow fish than green fish. 60 percent of the fish are yellow. How many green fish are in the aquarium?
kompoz [17]

9514 1404 393

Answer:

  6

Step-by-step explanation:

If 60% are yellow, the other 40% are green. Then the difference between yellow and green is 60% -40% = 20% of the total number of fish. That difference also happens to be half of the number of green fish:

  20% = (1/2)(40%)

So, the number of green fish is 2×3 = 6.

_____

If you wanted to, you could write a couple of equations:

  y - g = 3

  y = 0.60(y +g)

Using the first equation to write an expression for y, we get ...

  y = g +3

Using this in the second equation, we have ...

  g +3 = 0.6(g +3 +g)

  g +3 = 1.2g +1.8 . . . . eliminate parentheses

  1.2 = 0.2g . . . . . . . .  subtract g+1.8

  1.2/0.2 = g = 6 . . . . . divide by 0.2

There are 6 green fish in the aquarium.

6 0
3 years ago
A.Directions: Solve the system of equations by substitution and elimnination. Check your solutions.
Daniel [21]

Answer:

I had done already.thanks for huge point and heart.

7 0
3 years ago
Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum
lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\

\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\  (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\

=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3}  \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\

4 0
2 years ago
What is the square root of 98 round to the nearest tenth?
meriva
The square root of 98 is 9.899<span> so I think if it was rounded to the nearest tenth it would be 9.9</span>
4 0
3 years ago
Read 2 more answers
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