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1 year ago

J = x*2 − 0.49

Mathematics

1 answer:

AVprozaik [17]1 year ago

7 0

According to the given information the result: m < k < j

The correct option is E.

<h3>What is negative integer?</h3>

A number with a minus (-) sign before it is said to be negative if its value is always less than zero. The left side of zero on a number line is where negative numbers are displayed. A couple more negative values include -6 and -15.

<h3>According to the given information:</h3>

Given that x is a negative integer, j must be positive because the least negative number, which is k, yields a negative number when squared. Also negative will be m.

J has the largest value, as far as we are aware.

For all x values, it is impossible to compare k and m. When x=1 and k=1 respectively, m and k are smaller.

To know more about negative integer visit:

brainly.com/question/15276410

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3 years ago

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3 years ago

12n^3 + 16n^3 can someone please help me with this?

vodka [1.7K]

Answer:

$4n^{3} (3n^{2} + 4)$

Step-by-step explanation:

Assuming the problem is asking you to factor out the formula, it can be done easily by finding a common number with the two givens.

4 goes into both 12 and 16 evenly, so we will use this to factor. But that's not all, we have the n-variable to worry about.

Look at the n-variable exponents in the problem, take the highest power that can go be subtracted from both and use that. We have a $n^{5}$ and $n^{3}$ . Since 5 can't go into 3, we must use 3 to factor.

Our factoring variable will therefore be $4n^{3}$ . Now, use this to simply divide and get the answer:

$( 12n^{5} + 16n^{3} ) / 4n^{3} = 4n^{3}(3n^{2} + 4)$

So how did we get this? For the whole numbers, we have to divide: (12/4, 16/4). Next, we have to minus the exponents since we are dividing.

When dividing the 12 and 4, minus the $n^{5}$ and $n^{3}$ to get $n^{2}$ . Get rid of the $n^{3}$ term for the 16 and leave the 4. And there's your answer!

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3 years ago