What is X/60=700 ? Plz help it's due tomorrow

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RUDIKE [14]

B.) 95 is the answer

8 0

3 years ago

Which expression finds the measure of an angle that is coterminal with a 300° angle?

icang [17]

The expression that gives an angle that is coterminal with 300 is 300-720. Two angles are said to be coterminal if when they are drawn in a standard position, their terminal sides are on the same location. The expression gives an angle of 420 where when it is drawn the terminal sides are on the same location with the 300.

Someone asked the same question here before, check it out

3 0

3 years ago

Read 2 more answers

Identify the vertex of the parabola and tell whether it is a minimum or a maximum.

frozen [14]

Answer:

First parabola's vertex is (-2,2), which is a minimum.

Second parabola's vertex is (3,2), which is a maximum.

Step-by-step explanation:

Simply, a vertex of a quadratic is a graph's turning point.

The maximum and minimum can be identified by seeing if the graph curves up or down.

Maximum occurs when your graph is facing down.

Minimum occurs when your graph is facing up.

3 0

2 years ago

a sandwich shop has 60 stores and 70 percent of the stores are I California. How many stores are in California and Nevada

Aliun [14]

Answer:

The number of stores in California 42

The number of stores in Nevada 18

Step-by-step explanation:

Given as :

The total sandwich shop in California and Nevada = 60

The percentage of shop in California = 70%

So, The percentage of shop in Nevada = 100% - 70% = 30%

Let The number of stores in California = c

And The number of stores in Nevada = n

Now, According to question

The number of stores in California = 70% of the total number of shops

I.e c = $\frac{70}{100}$ × total number of shops

Or, c = $\frac{70}{100}$ × 60

∴ c = $\frac{70\times 60}{100}$

or, c = $\frac{4200}{100}$

or, c = 42

So, The number of stores in California = c =42

Again

The number of stores in Nevada = 30% of the total number of shops

I.e n = $\frac{30}{100}$ × total number of shops

Or, n = $\frac{30}{100}$ × 60

∴ n = $\frac{30\times 60}{100}$

or, n = $\frac{1800}{100}$

or, n = 18

So, The number of stores in Nevada = n = 18

Hence The number of stores in California 42

And The number of stores in Nevada 18 Answer

8 0

3 years ago

Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke

Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using reductio ad absurdum. Assume that $\sqrt{3}=\frac{m}{n}$ where $m$ and $n$ are non negative integers, and the fraction $\frac{m}{n}$ is irreducible, i.e., the numbers $m$ and $n$ have no common factors.

Now, squaring the equality at the beginning we get that

$3=\frac{m^2}{n^2}$ (1)

which is equivalent to $3n^2=m^2$ . From this we can deduce that 3 divides the number $m^2$ , and necessarily 3 must divide $m$ . Thus, $m=3p$ , where $p$ is a non negative integer.

Substituting $m=3p$ into (1), we get

$3= \frac{9p^2}{n^2}$

which is equivalent to

$n^2=3p^2$ .

Thus, 3 divides $n^2$ and necessarily 3 must divide $n$ . Hence, $n=3q$ where $q$ is a non negative integer.

Notice that

$\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}$ .

The above equality means that the fraction $\frac{m}{n}$ is reducible, what contradicts our initial assumption. So, $\sqrt{3}$ is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, $r\in\mathbb{Q}$ , which is equivalent to say that $r=\frac{m}{n}$ where $m$ and $n$ are non negative integers. Also, assume that $k\in\mathbb{Z}$ . So, we want to prove that $k\cdot r\in\mathbb{Z}$ . Recall that an integer $k$ can be written as

$k=\frac{k}{1}$ .

Then,

$k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}$ .

Notice that the product $mk$ is an integer. Thus, the fraction $\frac{mk}{n}$ is a rational number. Therefore, $k\cdot r\in\mathbb{Q}$ .

3. Let us prove by reductio ad absurdum that the sum of a rational number and an irrational number is an irrational number. So, we have $x$ is irrational and $p\in\mathbb{Q}$ .

Write $q=x+p$ and let us suppose that $q$ is a rational number. So, we get that

$x=q-p$ .

But the subtraction or addition of two rational numbers is rational too. Then, the number $x$ must be rational too, which is a clear contradiction with our hypothesis. Therefore, $x+p$ is irrational.

7 0

3 years ago