3 years ago

How many 12-digit decimal sequences are there that start and end with a sequence of at least two 3s?

1 answer:

6 0

Four positions of such a sequence are given to be 3s, and we have 10 choices for the remaining eight positions. So the number of such sequences is

$1^4\cdot10^8=10^8=100,000,000$

or 100 million.

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A right triangle has side lengths 7, 24, and 25 as shown below.

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Answer:

SinL = 7/25

CosL = 24/25

TanL = 7/24

Step-by-step explanation:

Find the diagram attached.

Using SOH CAH TOA in trigonometry identity to find the sinL, cosL and TanL

Note that the hypotenuse is the longest side = 25

The opposite will be the side facing the acute angle L

Opposite = 7

Adjacent = 24

For SinL

sinL = Opposite/Hypotenuse {SOH}

SinL = 7/25

For cosL:

CosL = Adjacent/Hypotenuse{CAH}

CosL = 24/25

For tanL:

TanL = Opposite/Adjacent {TOA}

TanL = 7/24

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