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jasenka [17]
3 years ago
6

How many 12-digit decimal sequences are there that start and end with a sequence of at least two 3s?

Mathematics
1 answer:
stiks02 [169]3 years ago
6 0
Four positions of such a sequence are given to be 3s, and we have 10 choices for the remaining eight positions. So the number of such sequences is

1^4\cdot10^8=10^8=100,000,000

or 100 million.
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See Below.

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