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kari74 [83]
3 years ago
6

A scientist is performing a study on mosquitoes. She collects water with mosquito larvae and places it in an enclosed container

in her lab. The scientist uses data from the study to create the function, M(t)=-3t^2+57t-144, where t is the number of days in the study.
Part A: Which equivalent form of M(t) reveals when the mosquitoes first appeared in the container and when there were no more mosquitoes in the container?

Part B: How long were there mosquitoes in the container?
Please show the work love yaa.
Mathematics
1 answer:
frez [133]3 years ago
4 0

Answer:

M(t) = -3 (t - 16) (t - 3)

Step-by-step explanation: Assuming you are working on the practice book - section 5: quadratic equations and functions than this is the correct answer to your question. Although there is another question below the on you have asked on in the actual textbook so if you need help on that just ask me in the comments below.

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Please help answer <br> Will give Brainlst
Artyom0805 [142]

Answer:

x= -3

y= -5

Step-by-step explanation:

10y - 3x = -41

+

-5y + 3x = 16

10y + (-5y) = 5y

-3x + 3x = 0

-41 + 16 = -25

5y + 0 = -25

y = -25/5

y= -5

10y -3× = -41

(10×-5) - 3x = -41

- 3x = - 41 + 50

- 3x = 9

x = -3

4 0
3 years ago
Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right).

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be z (x) = \cos x the base formula, where x is measured in sexagesimal degrees. This expression must be transformed by using the following data:

T = 180^{\circ} (Period)

z_{min} = -4 (Minimum)

z_{max} = 5 (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of 2\pi radians. In addition, the following considerations must be taken into account for transformations:

1) x must be replaced by \frac{2\pi\cdot x}{180^{\circ}}. (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

\Delta z = \frac{z_{max}-z_{min}}{2}

\Delta z = \frac{5+4}{2}

\Delta z = \frac{9}{2}

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

z_{m} = \frac{z_{min}+z_{max}}{2}

z_{m} = \frac{1}{2}

The new function is:

z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)

Given that z_{m} = \frac{1}{2}, \Delta z = \frac{9}{2} and T = 180^{\circ}, the outcome is:

z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

8 0
3 years ago
Find the Discriminant, and determine the number of roots
scoundrel [369]
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8 0
3 years ago
Find the missing terms of the geometric sequence.
Debora [2.8K]
Funny cause I just did something similar a few minutes ago

6 0
3 years ago
Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the
Alborosie

Answer:

Step-by-step explanation:

Let the subscripts d and n represent day and night respectively

The null hypothesis is

H0 : μd ≥ μn

The alternative hypothesis is

H1 : μd < μn

it is a one-tailed and also a right left test because of the greater than symbol in the alternative hypothesis.

The decision rule is to reject H0: μd ≥ μn If 0.10 > p value

Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)

z = (xd - xn)/√σd²/nd + σn²/nn

Where

xd and xn represents sample means for day and night respectively.

σd and σn represents population standard deviations for day and night respectively.

nd and nn represents number of samples

From the information given,

xd = 334

xn = 341

σd = 23

σ2 = 28

nd = 60

nn = 68

z = (334 - 341)/√23²/60 + 28²/68

= - 7/√20.34607843138

z = - 1.55

From the normal distribution table, the probability value corresponding to the z score is 0.061

Since the level of significance, 0.1 > 0.061, we would reject H0

Therefore, there is enough evidence to conclude that there are more units produced on the night shift than on the day shift.

8 0
3 years ago
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