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4 years ago

Decompose 3/4 into 6 equal lengths

2 answers:

4 0

I think drawing a picture will help you solve this one.

Draw a rectangle and divide it into 4 parts lengthwise (so it looks equal).

Cross 1/4 out so you have 3/4.
Divide each section of your 3/4 in half and you should get your 6 equal lengths.

Lostsunrise [7]4 years ago

4 0

Basically its 3/4 divided by 6

3/4 divided by 6 = 3/4 * 1/6 = 3/24 = 1/8

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-4<img src="https://tex.z-dn.net/?f=%5Cgeq" id="TexFormula1" title="\geq" alt="\geq" align="absmiddle" class="latex-formula">4(6

Ivan

-4 _> 4(6y-12)-2y

first distribute/ simplify the equation
-4 _> 24y-48-2y

then combine like terms
-4 _> 22y-48

solve for y

-4 _> 22y-48
44 _> 22y
2 _> y

so the answer is y <_ 2 ( y is less than or equal to 2)

4 0

4 years ago

1!+2(2!)+3(3!)+...+n(n!)=(n+1)!-1

anyanavicka [17]

Step-by-step explanation:

OK, let's assume it this way:

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!=(2.1!-1!)+(3.2!-2!)+(4.3!-3!)+...+((n-1)n!-n!)=(2!-1!)+(3!-2!)+(4!-3!)+

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!=(2.1!-1!)+(3.2!-2!)+(4.3!-3!)+...+((n-1)n!-n!)=(2!-1!)+(3!-2!)+(4!-3!)+...+(n+1)!-n!=(n+1)!-1!=(n+1)!-1

and boom problem solved

7 0

2 years ago

Runner A crosses the starting line of a marathon and runs at an average pace of 5.6 miles per hour. Half an hour later, Runner B

marishachu [46]

Time it took runner A to complete the marathon = 26.2 / 5.6 = 4 hrs 41 mins
Time it took runner B to complete the marathon = 26.2 / 6.4 = 4 hrs 6 mins

Time it took runner B to complete the marathon relative to when runner A started = 30 mins + 4 hrs 6 mins = 4 hrs 36 mins

Therefore, runner B will finnish ahead of runner A.

Let x be the time the two runners are at the same point, then
5.6x + 5.6(0.5) = 6.4x
6.4x - 5.6x = 2.8
0.8x = 2.8
x = 2.8/0.8 = 3.5
Therefore, runner B will catch up with runner A 3.5 hours after runner A starts the race.
Runner B; Runner B will catch up to Runner A 3.5 hours after Runner A crosses the starting line.

5 0

3 years ago

Javier rode his bike for a total of 40 minutes. The number of minutes he rode after lunch is 4 times the number of minutes he ro

Greeley [361]

Javier rode his bike for a total of 40 minutes.

Let x be the minutes Javier ride after lunch

Let y be the minutes Javier ride before lunch

The number of minutes he rode after lunch is 4 times the number of minutes he rode before lunch

x = 4 y

The number of minutes he rode after lunch + number of minutes he rode before lunch = 40

x + y = 40

We know x= 4y

4y + y = 40

5y = 40

y = 8

x= 4y so x= 4(8) = 32

Javier ride 32 minutes after lunch

7 0

3 years ago

What is the answer to 6+2times 5 ????

12345 [234]

6+2=8, right? Okay. Next, all you have to do is take away the equation "6+2". Now what you have is... 8x5. That's easy! 40. This is a very easy problem if you think about it.

3 0

3 years ago

Read 2 more answers