C
Using Descartes' rule of signs
look for the number of sign changes in f(x)
+ / + / - / -
There is 1 sign change hence 1 positive zero
f(-x) = -x³ + x² + 8x - 8
look for the number of sign changes in f(- x)
- / + / + / -
there are 2 sign changes hence 2 possible negative zeros
Answer:Yes,No,No,Yes
Step-by-step explanation:
Answer:
The expression equal to 2x^(2)+8 is:
First option (2x-4i)(x+2i)
Step-by-step explanation:
If we multiply
(2x-4i)(x+2i)=(2x)(x)+(2x)(2i)-(4i)(x)-4i(2i)
(2x-4i)(x+2i)=2x^(1+1)+4xi-4xi-8i^(1+1)
Simplifying:
(2x-4i)(x+2i)=2x^2-8i^2
and i^2=-1, then:
(2x-4i)(x+2i)=2x^2-8(-1)
Multiplying:
(2x-4i)(x+2i)=2x^2+8
Answer:
5.8931
⋅
10^
−
4
Step-by-step explanation:
Expanded Form:
0.00058931
