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Ira Lisetskai [31]
3 years ago
13

Find the sum of the measure of the interior angles of a 22-gon

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0
The formula for finding the interior angle sum of any polygon is (n - 2) x 180 where n is the number of sides, so...
(22 - 2) x 180 = 20 x 180 = 3,600 so the interior angles of a 22 sided polygon sum to 3,600 degrees.
Hope this helps :)
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Answer:

\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n

Step-by-step explanation:

Given expression : \sum_{n=3}^{20}(n(n+1))

Solving further :

\Rightarrow \sum_{n=3}^{20}(n^2+n)

\Rightarrow \sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n

So, \sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n

So, The given expression is equivalent to Option A

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Step-by-step explanation:

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