We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Ans(a):
Given function is 
we know that any rational function is not defined when denominator is 0 so that means denominator x+4 can't be 0
so let's solve
x+4≠0 for x
x≠0-4
x≠-4
Hence at x=4, function can't have solution.
Ans(b):
We know that vertical shift occurs when we add something on the right side of function so vertical shift by 4 units means add 4 to f(x)
so we get:
g(x)=f(x)+4

We may simplify this equation but that is not compulsory.
Comparision:
Graph of g(x) will be just 4 unit upward than graph of f(x).
Ans(e):
To find value of x when g(x)=8, just plug g(x)=8 in previous equation





4x-3x=-1-16
x=-17
Hence final answer is x=-17
A. 4.898979486
b. 7.416198487
c. 8.544003745
i think at least
change in y/change in x
y2-y1/x2-x1
-1--5/0-2
-1+5/-2
4/-2
-2
slope is -2
now take one ordered pair and plug it into the equation (for this example i will use the SECOND ordered pair
y = -2x +b
-1 = -2(0)+b
-1 = b
the equation is
<h2>
y = -2x - 1</h2>