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3 years ago

Does the graph represent a function?

Mathematics

1 answer:

Schach [20]3 years ago

3 0

Answer: NO

Step-by-step explanation:

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The graph of F(x), shown below, resembles the graph of G(x)= x², but it has

NNADVOKAT [17]

The equation of the function is F(x) = -3(x-4)² +4 , the correct answer is Option D

The missing graph is attached with the answer

<h3>What is a function ?</h3>

A function is a law that relate the independent variable and the dependent variable.

It is given that

The graph of F(x), shown below, resembles the graph of G(x)= x², but it has been changed

From the graph, it is seen that,

G(x) when shifted by -4 on the negative x axis.

and graph shifted by +4 on the positive y axis.

F(x) is scaled by a factor of -⅓ of G(x)

it is reflected across the x-axis.

So the equation of the function is

F(x) = -3(x-4)² +4

Therefore , the correct answer is Option D.

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8 0

2 years ago

Sandy makes 15.5 gallons of lemonade. She must refill the container after filling 100 drink cups. How much lemonade was in each

faltersainse [42]

100 divided by 15.5 = 0.155

5 0

4 years ago

(b) A $150 bonus was awarded to the three salespeople, which they had to share. It was awarded so that each salesperson received

fiasKO [112]

Each person made $50.
150 divided by 3 = 50.

6 0

3 years ago

Find the coordinates of the point in the first quadrant at which the tangent line to the curve (x)^3-xy+(y)^3 =0 is parallel to

Oksanka [162]

Differentiate implicitly:
 $3x^2-y-xy'+3y^2y'=0$

Solve for y
 $y'(3y^2-x)=y-3x^2
\\
\\y'={y-3x^2\over3y^2-x}$

When the tangent is parallel to the x-axis we have y'=0, so we must solve
 $y'={y-3x^2\over3y^2-x}=0\implies y=3x^2$

To find the actual value of x we plug this expression for y into the original equation
 $x^3-3x^3+27x^6=0
\\
\\x^3(27x^3-2)=0\implies x=\{0,{\sqrt[3]2\over3}\}$

Plugging this into the formula for y above gives the points
 $(0,0)\text{ and }({\sqrt[3]2\over3},{\sqrt[3]4\over3})$

which is where our tangent will be parallel to the x-axis.

8 0

3 years ago

I have no idea how to do this, someone help me

julsineya [31]

Try this:
1) for square a=5*2=10.
for circle r=5.
2) for square S'=10²=100; for circle S°=πr²≈78.54.
3) for half of circle S₁=0.5*78.54=39.27
4) for shaded region S=S'-S₁=100-39.27≈60.73
Answer: G (60.73)

6 0

3 years ago