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I am Lyosha [343]
2 years ago
5

What are the coordinates of the vertex of the parabola y=x^2+2x-1

Mathematics
1 answer:
kozerog [31]2 years ago
3 0
Y = x^2 + 2x - 1 = x^2 + 2x + 1 - 1 - 1 = (x + 1)^2 - 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).

Therefore, the vertex of y =  (x + 1)^2 - 2 is (-1, -2)
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Free_Kalibri [48]

Answer:

See below

Step-by-step explanation:

images attached showing all working

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3 years ago
The diagram below shows a shaded parallelogram drawn inside a rectangle. Using Pythagoras, find the hypotenuse of triangle A and
Julli [10]

Answer: 5.9 cm for both triangles.

Step-by-step explanation:

Hi, since the situation forms 2 right triangles we have to apply the Pythagorean Theorem:  

c^2 = a^2 + b^2  

Where c is the hypotenuse of a triangle (the longest side of the triangle) and a and b are the other sides.  

Replacing with the values given:  

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c = 5.9 cm

Since both triangles are identical ( same side lengths) the hypotenuse is the same for both, 5.9 cm.

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5 0
2 years ago
What is the factor tree of 99 and 165 and what is the GCF?
Shtirlitz [24]
99
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165
/ \
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5 0
3 years ago
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Ymorist [56]

Answer:

no

Step-by-step explanation:

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2 years ago
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Do u have an attachment?? :)
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2 years ago
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