Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
30cm, 60cm
Step-by-step explanation:
Given data
Dimensions of the first rectangle
Length =10cm
Width =20cm
We are told that the dimensions of the second rectangle is gotten by multiplying the first rectangle by 3
Hence the dimensions of the second rectangle is
Length =10*3= 30cm
Width = 20*3= 60cm
Here let us first write the value of each number:
6 thousands means 6*1000=6000.
9 hundreds means 9*100=900.
12 tens means 12*10 =120
10 ones means 10*1 =10
3 tenths means 3/10 =0.3
Now we just have to add all these values to get the final number.
adding 6000 + 900 +120 +10 +0.3 = 7030.3
So the final number is 7030.3
Answer:
A and C luv <3
Step-by-step explanation:
