Hello :
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2k</span>π or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
<span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
</span>k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2
Answer:
It's just c
Step-by-step explanation:
That's what corresponding angles look like? I don't really know how to explain this. Sorry!
Answer:
The solution is (2, -2)
Step-by-step explanation:
In order to solve this, multiply the second equation by -5 and then add through.
5x - 4y = 18
-5x - 15y = 20
------------------
-19y = 38
y = -2
Now that we have the value of y, we can solve for x.
x + 3y = -4
x + 3(-2) = -4
x - 6 = -4
x = 2
Answer: Length = 24; width =4
Step-by-step explanation
Since the ratio of the length to width is 6:1
Let the length be represented as 6x
And the width be = x
Such that that the Perimeter of the rectangle which is
Perimeter = 2(length + width) becomes
56 = 2(6x + x)
56/2 = 6x+x
28 = 7x
x = 4
Width = 4
Length = 6x= 6 x 4 = 24
F(2)=42(2)-100
f(2)= -16
f(2)/-16= -8
