<span>infinite number of significant figures would be your answer </span>
Answer:hahahha
Step-by-step explanation:
Ima just type to get points lol
There are 6C3 = 20 such combinations.
abc, abd, abe, abf
acd, ace, acf, ade
adf, aef, bcd, bce
bcf, bde, bdf, bef
cde, cdf, cef, def
You mean their sum is 12?
A) x + y = 12
B) x -y = 4 then we add both equations:
2x = 16
x = 8
y = 4
The fourth one 12.5!
It's self-explanatory, hope this helps!