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3 years ago

Find the area of a Trapezium

Mathematics

2 answers:

krek1111 [17]3 years ago

8 0

Area= ((base1+base2)/2)height

base1=3

base2=9

height=5

plug-in the values and do the math

this applies to all trapezoids

muminat3 years ago

5 0

Trapezoid* :)
Idk the answer tho sorry lol

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UCF is a major Metropolitan University located in Orlando Florida. UCF is advertising their bachelor in Economics with the stati

Arlecino [84]

Answer:

The claim is rejected

Step-by-step explanation:

Claim: UCF is advertising their bachelor in Economics with the statistic that the starting salary of a graduate with a bachelor in economics is $ 48,500 according to Payscale (2013-13).

Null hypothesis: $H_0: \mu = 48500$

Alternate hypothesis : $H_a : \mu \neq 48500$

n = 50

Since n is more than 30 .

So we will use Z test

x=43350

Standard deviation = 15000

$Z=\frac{x-\mu}{\frac{s}{\sqrt{n}}}\\Z=\frac{43350-48500}{\frac{15000}{\sqrt{50}}}\\Z=-2.42$

Refer the z table

p value = 0.00776

$\alpha = 0.01$

p value < $\alpha$

So, We are failed to accept null hypothesis

Hence The claim is rejected

5 0

3 years ago

If gas prices are now $3.75 and they were up 10% from 6 months ago, how much were gas prices 6 months ago?

Hatshy [7]

Given

gas prices are now $3.75 and it up 10% from 6 months ago.

Find out how much were gas prices 6 months ago.

To proof

gas prices now = $3.75

let the gas price 6 month ago = x

gas price now is rise up 10% from 6 months ago

First write 10% in simpler form

$= \frac{10}{100}$

= 0.1

Now the equation becomes

0.1x + x = 3.75

1.1x = 3.75

$x =\frac{3.75}{1.1}$

x = 3.41 (approx)

Thus gas prices 6 months ago be $ 3.41 (approx )

Hence proved

7 0

3 years ago

Alec's password consists of 1 letter and 4 digits. What is the probability of correctly guessing Alec's password?

valentinak56 [21]

Answer:

11A22

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the value of each variable:

Leona [35]

Answer:

5√3 = b

5 = d

10√3 = a

15 = c

Step-by-step explanation:

Sin60° = opp/hyp

sin60° = b/10

10sin60° = b

5√3 = b

Cos60° = adj/hyp

Cos60° = d/10

10Cos60° = d

5 = d

Sin30° = opp/hyp

Sin30° = 5√3/a

a = 5√3/Sin30°

a = 10√3

Tan30° = opp/adj

Tan30° = 5√3/c

c = 5√3/tan30°

c = 15

3 0

3 years ago

Carla wants to start a college fund for her daughter Lila. She puts $63,000 into an account that grows at a rate of 2.55% per ye

Oksanka [162]

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 63000

r = 2.55% = 2.55/100 = 0.0255

n = 12 because it was compounded 12 times in a year.

Therefore, function, C(t), that represents the amount of money in the account t years after the account is opened is

C(t) = 63000(1 + 0.0255/12)^12t

C(t) = 63000(1.002125)^12t

For C(t) = 100000,

100000 = 63000(1.002125)^12t

100000/63000 = (1.002125)^12t

1.587 = 1.002125)^12t

Taking log of both sides

Log 1.587 = log 1.002125)^12t

Log 1.587 = 12tlog 1.002125)^

0.2005 = 12t × 0.00092

0.2005 = t × 0.01104

t = 0.2005/0.01104

t = 18.16 years

5 0

3 years ago