A=pR^2-2pr^2, since R=15 and r=7.5
A=225p-112.5p
A=112.5p
A≈353.25 ft^2
Angles 4 and 6 are called Alternate Exterior Angles
Step-by-step explanation:
Alternate Exterior Angles are a pair of angles on the outer side of the each of two lines but on opposite sides of the transversal.
When we take two parallel lines they will create 8 angles, such as 1,2,3,4,5,6,7 & 8.
In that angle 6 is 65 degrees.
Angles 1,2,3 & $ are in one line and remaining four angles on other line.
So Angles 4 and 6 are alternate exterior angles.
The formula is width times length
Answer number 3
Step-by-step explanation:
