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erica [24]
3 years ago
5

7. If f(x) = -8x +11, find f(-4).​

Mathematics
2 answers:
Tomtit [17]3 years ago
5 0

Answer:

F(-4)=43

Step-by-step explanation:

1.Replace X to -4

f(-4)= -8(-4)+11

2.Solve

Multiplying two negative give you a positive (-8 x -4=32).

Then you Add.

32+11=43.

<em>Hope this help!</em>

kobusy [5.1K]3 years ago
3 0

Answer:

Step-by-step explanation:

So

f(x) = -8x +11, for f(-4).​

= -8(-4)+11

= 32 + 11

= 43

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HELP!! 50 POINTS!!!
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Step-by-step explanation:

We have been given a table, which represents the projected value of two different houses for three years.


Part A:

\text{Increase in value of house 1 after one year}=294,580-286,000

\text{Increase in value of house 1 after one year}=8580

\text{Increase in value of house 1 after two years}=303,417.40-294,580

\text{Increase in value of house 1 after two years}=8837.4

We can see from our given table that the value of house 1 is not increasing at a constant rate, while a linear function has a constant rate of change, therefore, an exponential function can be used to describe the value of the house 1 after a fixed number of years.

\text{Increase in value of house 2 after one year}=295,000-286,000

\text{Increase in value of house 2 after one year}=9,000

\text{Increase in value of house 2 after two years}=304,000-295,000

\text{Increase in value of house 2 after two years}=9,000

We can see from our given table that the value of house 2 is increasing at a constant rat that is $9,000 per year. Since a linear function has a constant rate of change, therefore, a linear function can be used to describe the value of the house 2 after a fixed number of years.

Part B:

Let x be the number of years after Dominique bought the house 1.

Since value of house 1 is increasing exponentially, so let us find increase percent of value of house 1.

\text{Increase }\%=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100

\text{Increase }\%=\frac{294,580-286,000}{286,000}\times 100

\text{Increase }\%=\frac{8580}{286,000}\times 100

\text{Increase }\%=0.03\times 100

\text{Increase }\%=3

\text{Increase }\%=\frac{303,417.40-294,580}{294,580}\times 100

\text{Increase }\%=\frac{8837.4}{294,580}\times 100

\text{Increase }\%=0.03\times 100

\text{Increase }\%=3

Therefore, the growth rate of house 1's value is 3%.

Since we know that an exponential function is in form: y=a*b^x, where,

a = Initial value,

b = For growth b is in form (1+r), where, r is rate in decimal form.

3\%=\frac{3}{100}=0.03

Upon substituting our values in exponential function form we will get,

f(x)=286,000(1+0.03)^x, where, f(x) represents the value of the house 1, in dollars, after x years.

Therefore, the function f(x)=286,000(1.03)^x represents the value of house 1 after x years.

Let x be the number of years after Dominique bought the house 2.

We can see that when Dominique bought house 2 it has a value of $286,000. This means that at x equals 0 value of house will be $286,000 and it will be our y-intercept.

Since value of house 2 is increasing 9000 per year, therefore, slope of our line be 9000.

Upon substituting these values in slope-intercept form of equation (y=mx+b) we will get,

f(x)=9000x+286,000, where, f(x) represents the value of the house 2, in dollars, after x years.

Therefore, the function f(x)=9000x+286,000 represents the value of house 2 after x years.

Part C:

Since values in exponential function increases faster than linear function, so the value of house 1 will be greater than value of house 2.

Let us find the value of house 1 and house 2 by substituting x=25 in our both functions.

f(25)=286,000(1.03)^{25}

f(25)=286,000*2.0937779296542148

f(25)=598820.48788

We can see that value of house 1 after 25 years will be approx $598,820.48.

f(25)=9000*25+286,000

f(25)=225,000+286,000

f(25)=511,000

We can see that value of house 2 after 25 years will be approx $511,000.

Since $511,000 is less than $598820.48, therefore, value of house 1 is greater than value of house 2.

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