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shusha [124]
3 years ago
10

Allison drew 3 triangles, 5 hexagons, and 4 octagons.

Mathematics
2 answers:
Nesterboy [21]3 years ago
8 0

Answer:

71

Step-by-step explanation:

3×3 = 9

5×6 = 30

4 × 8 = 32

30+32+9= 71

Ber [7]3 years ago
3 0

Answer:

D 68

Step-by-step explanation:

I think that's the answer

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the length of a rectangle is 5 centimeters less than its width. what are the dimensions of the rectangle if it’s area is 176 squ
Allushta [10]

11 is the length

16 is the width

3 0
3 years ago
- What is 5) 11 written as a decimal?
Vlada [557]

Answer:

Step-by-step explanation:

11 written as a decimal is

0.11

move the point from 11 over to right two times (;

4 0
3 years ago
PLEASE HELP!!!<br> Hshehebsjahsvsvabsbbsbs
IRISSAK [1]

Answer:

i think its like 9.14 or sumthin

Step-by-step explanation:

is tht NWEA? lol

5 0
3 years ago
b is the midpoint of AC and E is the midpoint of BD if A(-9,-4) C(-1,6) and E(-4,-3) find the coirdinates of D
natima [27]

To find the coordinate of the point D, we can use the Midpoint point of a line Segment formula. Calculation of the formula are as follows,

Given two points A(x1,y1) and C(x2,y2), we need to locate the midpoint coordinate of this line denoted as B(x,y).

To solve for the value of x and y, we get,

x=(x1+x2)/2 and y=(y1+y2)/2

For the given problem, we need to solve first the midpoint coordinate of AC which is B.

So, A(-9,-4)=A(x1,y1) and C(-1,6)=C(x2,y2)

Hence,

B(x,y)=B((-9+(-1))/2, (-4+6)/2)=B(-10/2,2/2)=B(-5,1)

Now, since the midpoint is given but one point in the line is missing. To solve for the missing point D(x2,y2), we need to use the Midpoint Segment Formula.

 That is, B(-5,1)=B(x,y) and E(-4,-3)=E(x1,y1)

So,

x=(x1+x2)/2 and y=(y1+y2)/2

-5=(-4+x2)/2 and 1=(-3+y2)/2

By Cross Multiplication and Transposing method,

-5(2)=-4+x2 and 1(2)=-3+y2

x2=-10+4=-6 and y2=3+2=5

Thus, the coordinate of D is D(-6,5).

5 0
4 years ago
Use the long division method to find the result when 6x^3 + 19x2^2 + 17x + 3 is
skelet666 [1.2K]

Answer:

\frac{6x^3 \ + \ 19x^2 \ + \ 17x \ + \ 3}{2x \ + \ 3}  \ = \ 3x^2 \ + \ 5x \ + \ 1

Step-by-step explanation:

Given;

F(x) = 6x³  +  19x²   +   17x   +  3

Factor of F(x) = 2x + 3

Using long division method;

                                   3x²  + 5x  +   1

                                 ------------------------------------

               2x + 3    √  6x³  +  19x²   +   17x   +  3

                             -  (6x³   +   9x²)

                                ----------------------------------------

                                               10x²    +    17x   +  3

                                          -   (10x²     + 15x)

                                             -------------------------------

                                                                  2x   +  3

                                                               - (2x   +  3)

                                                                 ---------------

                                                                         0

Thus, \frac{6x^3 \ + \ 19x^2 \ + \ 17x \ + \ 3}{2x \ + \ 3}  \ = 3x^2 \ + \ 5x \ + \ 1

                       

8 0
3 years ago
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