Question

NEED HELP ASAP!!!!!

Answer 1

Part A:

An isometric transformation is a type of transformation where the original shape and size of the pre-image is not altered in the image.

To show that the translation was an isometric transformation, we show that the distance between any two points in the pre-image is equal to the distance between the corresponding points in the image.

Consuder, line AB, the distance between point A and point B is given by:

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ = \sqrt{(-1-(-6))^2+(0-0)^2} = \sqrt{(-1+6)^2+0^2} \\ \\ = \sqrt{5^2+0} = \sqrt{25} =5$

The distance between point A' and point B' in the image is given by:

$d= \sqrt{(3-(-2))^2+(4-4)^2} \\ \\ = \sqrt{(3+2)^2+0^2} = \sqrt{5^2+0} \\ \\ = \sqrt{25} =5$

Similarly checking other points of the pre-image against the corresponding points of the image shows that the size of the pre-image is preserved in the image.



Part 2:

The translation that maps the triangle ABC onto its image are:
Triangle ABC was shifted 4 units to the right.
Triangle ABC was shifted 4 units up.

Answer 2

Answer:

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Step-by-step explanation: