All categories

3 years ago

I’m confused on this one

Mathematics

2 answers:

otez555 [7]3 years ago

7 0

Well a circle has 360 degrees and this question wants the degree of counter-clockwise.

I think first we subtract 69 from 360, since that is the rotation clockwise, to get the angle of rotation.

360 - 69 is 291 degrees

notsponge [240]3 years ago

4 0

The question is inconsistent. Asked about the angle of reflection above, and the angle of rotation below.

Assuming that question is asking for the single angle of rotation that replaces the double reflection.

The single angle of rotation is double the angle between the reflection axes, namely 2*69=138 degrees. Since the reflections are done in the counter-clockwise direction, so the rotation is in the same sense.

You might be interested in

Help appreciated !!!!

sergiy2304 [10]

Answer:

Step-by-step explanation:

The circle is divided into 5 sections. The probability that the needle lands on a particular color is equally likely.

So,

$P(red) = \frac{1}{5}\\\\P(green) = \frac{1}{5}\\\\$

Probability of not blue = 1 - Probability of blue

$= 1 - P(blue)\\\\=1 - \frac{1}{5}\\\\= \frac{4}{5}$

3 0

3 years ago

What is the range of the relation in the table below ???

natta225 [31]

Answer:

range : {0, 2, 4}

Step-by-step explanation:

write down the same range once.

4 0

3 years ago

SOLOVE THIS QUESTION PLSS

pantera1 [17]

Answer:

positive its 18 feet

Step-by-step explanation:

5 0

3 years ago

State the equation of the line that is perpendicular to 4x-3y=10 through the point (-2,4)

Lynna [10]

The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is $y-4=\frac{-3}{4}(x+2)$

Solution:

Given, line equation is 4x – 3y = 10

We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}$

We know that, slope of a line $\times$ slope of perpendicular line = -1

$\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}$

Now, slope of our required line = $\frac{-3}{4}$ and it passes through (-2, 4)

The point slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}$

$y-4=\frac{-3}{4}(x+2)$

Hence the equation of line is found out

6 0

3 years ago

help quick! if BC is parallel to DE, then all of the following are equivalent to each other except...

Alecsey [184]

Answer is letter c. (CE/AC)

8 0

3 years ago

Read 2 more answers