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kherson [118]
3 years ago
12

Questions 13 and 17 if anybody knows ?

Mathematics
1 answer:
jenyasd209 [6]3 years ago
8 0
13) If T(n) = 2n-7, what is the 5th term?
n is the number of the term you are looking for. In this instance, n is equal to 5.

T(5) = 2(5) - 7
T(5) = 10 -7
T(5) = 3

The 5th term is 3.

17) inequality based on the line number.
Since the line does not extend in any direction outward. It means that the range should be within -3 and 3. 
Solid circle means that -3 is equivalent to x
hollow ciccle means that 3 is not x.

-3 <u><</u> x < 3

x = any number from -3 upto 2.
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Find the midpoint between (-1+9i) and B=(5-3i)
sdas [7]

Answer:

2 + 3i, midpoint is (2,3)

Step-by-step explanation:

we need to find the midpoint between (-1+9i) and B=(5-3i)

To find the midpoint of two points (a+bi)  and (c+di) in a complex plane,  

we apply formula

\frac{a+c}{2} + \frac{b+d}{2} i

A = (-1+9i) and B=(5-3i)

Midpoint for AB is

\frac{-1+5}{2} + \frac{9+(-3)}{2}i

\frac{4}{2} + \frac{6}{2}i

2 + 3i , so midpoint is (2,3)


8 0
3 years ago
Read 2 more answers
An athlete eats 60 grams of protein per day while training. How much is this in milligrams?
lyudmila [28]
I believe the answer to be 60000 mg
6 0
3 years ago
Un número multiplicado 2 veces que me de 4633
lions [1.4K]

Answer:

2316

Step-by-step explanation:

divide 4633 por 2 y la respuesta es 2316 (no abra el enlace, te lleva a un sitio inapropiado)

3 0
3 years ago
A circular racetrack has a diameter of 1/2 mile. How far does a car travel in one lap around the track? Round to the nearest ten
dlinn [17]
Given:
Circular racetrack with a diameter of 1/2 mile

Find: how far does a car travel in one lap around the track?

We need to find the circumference of the racetrack.

Circumference is multiplying pi to the diameter of the racetrack.

Circumference = 3.14 * 1/2 mile
Circumference = 3.14/2 mile
Circumference = 1.57 miles rounded to the nearest tenth is 1.60 miles.
7 0
3 years ago
Pls help
solong [7]
Ok let’s solve it

5(x-2)^2-20=0

first let’s foil (x-2)

5(x^2-4x+4) -20=0

now distribute the 5

5x^2 -20x +20 -20 = 0

combine like terms

5x^2-20x=0

take the gcf

5x(x-4)=0

x=0, 4

solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k

7 0
3 years ago
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