Please Help ASAP!!! Question in image below.
1 answer:
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Answer:
see the procedure
Step-by-step explanation:
Looking at the graph we have
The graph represent a vertical parabola open upward
The vertex is a minimum
The vertex is the point (-4,-3)
The domain is the interval -----> (-∞,∞)
The Domain is all real numbers
The range is the interval ----> [-3,∞)
The range is all real numbers greater than or equal to -3
The graph is increasing in the interval (-4,∞)
The graph is decreasing in the interval (-∞,-4)
The minimum of the graph is y=-3 occurs at x=-4
9514 1404 393
Answer:
-3 ≤ x ≤ 19/3
Step-by-step explanation:
This inequality can be resolved to a compound inequality:
-7 ≤ (3x -5)/2 ≤ 7
Multiply all parts by 2.
-14 ≤ 3x -5 ≤ 14
Add 5 to all parts.
-9 ≤ 3x ≤ 19
Divide all parts by 3.
-3 ≤ x ≤ 19/3
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<em>Additional comment</em>
If you subtract 7 from both sides of the given inequality, it becomes ...
|(3x -5)/2| -7 ≤ 0
Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.
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For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...
|f(x)| < (some number) . . . . or ≤
If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:
|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0
Any solutions to these inequalities must respect their domains.
