Splitting up [0, 3] into
equally-spaced subintervals of length
gives the partition
![\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%20%5Cdfrac3n%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac3n%2C%20%5Cdfrac6n%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac6n%2C%20%5Cdfrac9n%5Cright%5D%20%5Ccup%20%5Ccdots%20%5Ccup%20%5Cleft%5B%5Cdfrac%7B3%28n-1%29%7Dn%2C%203%5Cright%5D)
where the right endpoint of the
-th subinterval is given by the sequence

for
.
Then the definite integral is given by the infinite Riemann sum

Answer and Step-by-step explanation:
1/2x is positive and 2 is negative, so they cross each other perpendicularly, and the equation needs to be at -13 y, 0 x
The answer is y = -2x - 13
#teamtrees #WAP (Water And Plant)
Answer:
Step-by-step explanation:
I need the answer too help
Answer:
I assume that the function is:

Now let's describe the general transformations that we need to use in this problem.
Reflection across the x-axis:
For a general function f(x), a reflection across the x-axis is written as:
g(x) = -f(x)
Reflection across the y-axis:
For a general function f(x), a reflection across the y-axis is written as:
g(x) = f(-x)
Then a reflection across the y-axis, and then a reflection across the x-axis is just:
g(x) = -(f(-x)) = -f(-x)
In this case, we have:

then:

Now we can graph this, to get the graph you can see below: