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nevsk [136]
3 years ago
11

A submersible is a type of underwater vessel. Suppose a submersible starts at a depth of 40 feet below sea level, represented by

–40 feet. The table shows the submersible's change in depth from one minute to the next.
Time and Depth of Submersible







2:15 p.m.

2:16 p.m.

2:17 p.m.

2:18 p.m.

–40 feet

180 feet lower

175 feet lower

185 feet lower

Answer the questions to find the depth of the submersible after 3 minutes.

1. Write and evaluate a subtraction expression to find the depth of the submersible at 2:16 p.m.
Mathematics
2 answers:
kotegsom [21]3 years ago
5 0

Answer:

580

no cap

Step-by-step explanation:

Rufina [12.5K]3 years ago
4 0
Answer is 580, and the write and evaluate would be 580 - 185 - 175 = 220
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Suppose a random sample of n measurements is selected from a binomial population with probability of success p = .39. Given n =
Oksi-84 [34.3K]

Answer:

The answer is below

Step-by-step explanation:

a) Given that the number of sample (n) = 300, therefore since n > 30, the distribution of the sample means is going to be normally distributed.

b) The mean of the distribution of sample means (also known as the Expected value of M) is equal to the population mean μ.

\mu_x=\mu=np=300*0.39=117

c) The standard deviation of the distribution of sample means is called the Standard Error of M, it is given by:

\sigma_x=\sqrt{np(1-p)} =\sqrt{300*0.39(1-0.39)} =8.44

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3 years ago
Question in picture please help!
EleoNora [17]

Answer:

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Step-by-step explanation:

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3 0
1 year ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
2 years ago
The Fun Committee is hosting the Annual City Festival. Jennifer is in charge of the committee and is planning a race to raise mo
nadya68 [22]

Answer: Hello your question some data but i will provide a general solution based on the scope of your question making some suggestions as well

answer : Summation of displacements ( back and forth distance ) / Number of Runners

Step-by-step explanation:

Given that ; the aim of the race is to raise money

The number of miles/ distance covered will determine how much money that would be raised

Formula to resolve the problem =  Summation of displacements ( back and forth distance ) / Number of Runners

<em>Lets assume: ( example ) </em>

<em> Distance between the Park and the City hall is = 6 miles </em>

<em>Number of runners = 4</em>

<em>Given that the runners Run  from the Park to the City hall and then run back</em>

<em>Total miles covered by each runner = ( 6 + 6 )/ 4  = 12/4 = 3 miles </em>

4 0
3 years ago
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