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Kryger [21]
4 years ago
5

The BCG has given specific names and descriptions to the four resulting quadrants in its growth-share matrix based on the amount

of cash they generate for or require from the organization. "Cash cows" are SBUs that are classified as having:___________
A. high market growth rates and high relative market shares.
B. low market growth rates but high relative market shares.
C. low market growth rates and low relative market shares.
D. high market growth rates but low relative market shares.
E. medium market growth rates and medium relative market shares.
Business
1 answer:
S_A_V [24]4 years ago
3 0

Answer:

low market growth, high relative market share

Explanation:

In 1970, Bruce D. Henderson created a certain growth-share matrix for the Boston Consulting group in which the cash cow was stated to be a company that operates in a slow-growing industry but with large market share.

Companies are known to love cash cows, reason being that they require minimal amount of money to maintain while the business on its own gives back much more money than one puts into it

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Answer:

D. Star will be liable on the contract only if it adopts the contract.

Explanation:

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Which feature is a point of differentiation between products and services
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Answer:

Products are tangible, offered by the companies to the customers in exchange for money.

Services are the intangible economic product that is provided by a person on the other person’s demand. It is an activity carried out for someone else.

Explanation:

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4 years ago
A major contribution of the Miller model is that it demonstrates, other things held constant, that ____
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Answer: The correct answer is "personal taxes lower the value of using corporate debt".

Explanation: A major contribution of the Miller model is that it demonstrates, other things held constant, that: <u>personal taxes lower the value of using corporate debt.</u>

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8 0
3 years ago
What is the answer pleas
pogonyaev

The third and fourth sentences are correct!

hope this help:))

6 0
3 years ago
Suppose the world population today is 7 billion, and suppose this population grows at a constant rate of 3% per year from now on
oksano4ka [1.4K]

Answer:

a) P(t=100) = 7 e^{0.03*100}=140.599 billion

b) P(t=0) = 7 e^{0.03*0}=7 billion

P(t=1) = 7 e^{0.03*1}=7.21 billion

P(t=2) = 7 e^{0.03*2}=7.43 billion

P(t=10) = 7 e^{0.03*10}=9.45 billion

P(t=25) = 7 e^{0.03*25}=14.82 billion

P(t=50) = 7 e^{0.03*50}=31.37 billion

c) Figure attached

d) Figure attached

Explanation:

The proportional model on this case would be given by:

\frac{dP}{dt} = kP

Where P is the population size, t the time on years and k a constant.

We can reorder this expression like this:

\frac{dP}{P} = k dt

If we integrate both sides we got:

ln|P| = kt + C

And using exponentials on both sides we got:

P(t) = e^{kt} e^C = P_o e^{kt}

Where P_o=7 billion  represent the initial amount for the starting year t=0.

The rate on this case is given r =3\% = 0.03, so then our model would be given by:

P(t) = 7 e^{0.03t}

Part a

For this case we just need to replace t=100 and we got:

P(t=100) = 7 e^{0.03*100}=140.599 billion

Part b

For this case we have the following:

P(t=0) = 7 e^{0.03*0}=7 billion

P(t=1) = 7 e^{0.03*1}=7.21 billion

P(t=2) = 7 e^{0.03*2}=7.43 billion

P(t=10) = 7 e^{0.03*10}=9.45 billion

P(t=25) = 7 e^{0.03*25}=14.82 billion

P(t=50) = 7 e^{0.03*50}=31.37 billion

Part c

The graph is on the first figure attached.

Part d

If we take a log-log scale we have the following values

We need to exclude the point t=0 since the natural log for 0 is not defined.

ln 1 =0 , ln 2= 0.693, ln 10=2.30, ln 25 =3.22, ln 50= 3.91

The result would be the figure 2 attached. And we see a better result for the graph.

3 0
3 years ago
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