3 years ago

Simplify the expression 2(6x + 3)

Mathematics

1 answer:

UNO [17]3 years ago

6 0

12x + 6 because 2 times 6 is 12 and 2 times 3 is 6

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Start solving the following x+5=11

dimulka [17.4K]

Answer:

Step-by-step explanation:

$x$ =11-5=6

therefore $x$ =6

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2 years ago

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Use the definitions and theorems of this section to evaluate and simplify the following expression. Be sure to express answers w

kirza4 [7]

$\bf (b^4)^2\implies b^{4\cdot 2}\implies b^8$

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3 years ago

What is the missing numerator?

den301095 [7]

Answer:

It is 2/7 please mark me brainliest

Step-by-step explanation:

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2 years ago

*^%Brainliest 15 pounds Question 5 (2 points)

galben [10]

Answer:

Step-by-step explanation:

Separate into two parts

$\frac{4xy^{3} }{2xy^{2} } + \frac{8x^{2} {y}^{5} }{2x {y}^{2} }$

Simplify:

This is for the first fraction

$\frac{4x {y}^{3} }{2x {y}^{2} } = (4 \div 2)(x \div x)( {y}^{3} \div {y}^{2} )$

$2(1)( {y}^{3 - 2} )$

$2{y}$

Now for the second fraction:

$\frac{8 {x}^{2} {y}^{3} }{2x {y}^{2} } = ( 8 \div 2)( {x}^{2} \div x)( {y}^{5} \div {y}^{2} )$

$4( {x}^{2 - 1} )( {y}^{5 - 2} )$

$4x {y}^{3}$

Add both parts together

$2y + 4x {y}^{3}$

To turn this into the said formula, that would become:

$2 {x}^{0} {y}^{1} + 4 {x}^{1} {y}^{3}$

Where:

a=0

b=1

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3 years ago

Solve C = 2πr (solve for "r")<br> C = 15

Jobisdone [24]

C = 2 pi r

but c = 15

15 = 2 pi r
15 = 2 * (22/7) * r
r = (15*7) / 2 / 22
r = 2.386

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3 years ago

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