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bija089 [108]
4 years ago
10

A pair of perpendicular line segments intersecting at which point would be the diagonals of a square inscribed in the circle? A)

(–2, 1) B) (–2, 2) C) (–1, 1) D) (–1, 2)
Mathematics
2 answers:
AlekseyPX4 years ago
4 0

Answer:

the correct answer is a

Step-by-step explanation:

igor_vitrenko [27]4 years ago
4 0

Answer:

A (-2,1)

Step-by-step explanation:

The pair of perpendicular line segments that are the diagonals of a square inscribed in the circle intersect at the circle’s center, which is (–2, 1).

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6x^2 + 66x + 60 factor completely
kiruha [24]

Hi! Let me help you!

  • Remember, factoring looks like so:
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3 0
2 years ago
The point A(-8, 6) is translated using T: (x,y) → (x + 5. y - 4). What is the distance from A to A'?
Vsevolod [243]
Translated means the points are moving across the plane without rotating or changing shape. In this case, the x-coordinate would be moving up 5 (x + 5) and the y-coordinate would be moving to the left 4 (y - 4).

A is (-8, 6). A' is the result of the translation from this point. The results of the solution above in A is the point (-3, 2) = A'.

Now you must find the distance between these two coordinates. To find the distance you must use the distance formula: √<span>(x2 - x1)^2 + (y2 - y1)^2. Since you now have two points, A and A', plug these into the distance formula.

</span>√(-3 - (-8))^2 + (2 - 6)^2
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The distance from A to A' is √41.
8 0
4 years ago
Read 2 more answers
What is the area of this composite figure? A figure is comprised of 1 rectangle and 2 triangles. The rectangle has a length of 1
Galina-37 [17]

Answer:

  256 cm^2

Step-by-step explanation:

The area of the rectangle is the product of its length and width.

  A = (16 cm)(10 cm) = 160 cm^2

The area of each triangle is half the product of its base and height.

  A = (1/2)(16 cm)(6 cm) = 48 cm^2

__

Then the area of the rectangle and 2 triangles is ...

  160 cm^2 + 2(48 cm^2)  = 256 cm^2

The area of the composite figure is 256 cm^2.

5 0
4 years ago
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