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3 years ago

I will mark you as brainlinest for correct answer!!!!!pleaseeeee help!!!!!!

Mathematics

2 answers:

VLD [36.1K]3 years ago

8 0

Hey there,

t2−4 and also n^2 - 225<span> would be your answer.

~Jurgen</span>

mel-nik [20]3 years ago

7 0

A^2 - b^2 = (a+b)(a-b)

answer :

t^2 - 1
n^2 - 225

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A BUSHEL OF APPLES WEIGHS ABOUT 42 POUNDS. THERE ARE 4 PECKS OF BUSHELS. IT TAKES 2 POUNDS OF APPLES TO MAKE ONE PIE. HOW MANY P

madam [21]

Answer:

84 pies

Step-by-step explanation:

if you multiply 42 pounds by4 pecks. You get 168 pounds. and then you divide that by 2 and you can make 84 pies

7 0

3 years ago

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts

Damm [24]

Answer:

t=2.08 seconds.

Step-by-step explanation:

Well, in this example, H(t)=-0.6cos(2pi/2.5)t+1.5 should be equal to 1.2. If calculated, -0.6cos(0.8pi)t=1.2-1.5 which is equal to -0.6cos(0.8pi)t=-0.3, then cos(0.8pi)t=0.5. The value of cosine in terms of radians when it is equal to 0.5 is pi/3. So, cos(0.8pi)t=cos(pi/3). If simplified, (0.8pi)*t=5pi/3. pi's are cancelled out and t is calculated as 2.08333... If rounded to the nearest hundredth it is 2.08.

4 0

3 years ago

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

4 years ago

Please help me with this math problem

givi [52]

It should be c really hope this helps and im right have a blessed day:)

5 0

3 years ago

A student studied for 1 hour and earned a 50% on her test. If she had studied for 2

marshall27 [118]

You have to double 1 and 50 to get 2 and 100

1:50 = 2:100

1x2=2

50x2=100

So the statement, <em>if she studied for 2 hours, she would have gotten 100%</em>, makes sense

Hope this helps!

3 0

3 years ago