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3 years ago

I will mark you as brainlinest for correct answer!!!!!pleaseeeee help!!!!!!

Mathematics

2 answers:

VLD [36.1K]3 years ago

8 0

Hey there,

t2−4 and also n^2 - 225<span> would be your answer.

~Jurgen</span>

mel-nik [20]3 years ago

7 0

A^2 - b^2 = (a+b)(a-b)

answer :

t^2 - 1
n^2 - 225

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Which equation shows the substitution method being used to solve the system of linear equations?

bonufazy [111]

B.
It says x = y + 3. So what they did was put y + 3 in the place of x.

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2 years ago

the length of my living rooom is 24 feet. the width of my living room is 1/2 the length. what is the area of my living room.

stich3 [128]

The width of my living room is 1/2 the length :

$24 \times \frac{1}{2} = 12 \: ft$

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$24 \times 12 = 288 \: {ft}^{2}$

Answer: 288

Ok done. Thank to me :>

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2 years ago

ANSWERS QUICKLY PLEASE

marshall27 [118]

It’s an irrational number (can’t be expressed as a fraction with two integers).

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3 years ago

There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am

Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

$n = 479, \pi = \frac{130}{479} = 0.2714$

Hence the bounds of the interval are found as follows:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112$

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago

what is the inverse of h(x)=12e^2x. based on your answer write an expression write an expression equivalent to where x is h of 1

dezoksy [38]

Let y = 12 e^2x

e^2x = y/12
Taking [email protected]
ln e^2x = ln (y/12)

2x = ln (y/12)

x = (1/2) ln (y / 12)

so the inverse h-1(x) = (1/2) ln ( x / 12)

3 0

3 years ago