Question

Solve the equation in the quadratic formula x^2-9x+14=0

Answer 1

$x^{2} -9x+14=0\\x= \frac{-b+- \sqrt{b^{2}-4ac}}{2a} \\x=\frac{-(-9)+- \sqrt{(-9)^{2}-4(1)(14)}}{2(1)}\\x=\frac{9+- \sqrt{81-56}}{2}\\x=\frac{9+- \sqrt{25}}{2}\\x=\frac{9+-5}{2}\\x=\frac{4, 14}{2}\\x=2, 7$

Answer 2

X^2-9x+14=0

X= -(-9)+_square root(-9)^2-4(1)(14)/2

X= 9+_Square Root 25/2

X= 9+_5/2

X= 9+5/2= 7

X= 9-5/2= 2

The Answer is: 7and 2.