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olga nikolaevna [1]
3 years ago
10

Simplify the expression: x^2+3x-28/x^2-7x+12. Show your work.

Mathematics
1 answer:
Sergio [31]3 years ago
6 0

(x+7)/(x-3)

All you have to do is write the equation, factor, and cancel like terms.

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Replace ∗ with a monomial so that the derived expression may be represented as a square of a binomial: * +14b+49
anyanavicka [17]

Answer:

  * = b²

Step-by-step explanation:

You know that the square of a binomial is of the form ...

  (x + y)² = x² + 2xy + y²

Matching given terms, we have ...

  49 = y²

  2xy = 14b

Solving the first of these relations for y, we have

  y = √49 = 7

Putting that in the second relation and solving for x, we find ...

  2x·7 = 14b

  14x = 14b

  x = b

Then the first term of the expansion, x², will be b².

The missing term is b².

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Consider the relation y = −8|x + 3| − 9. what are the coordinates of the vertex? (−3, 9) (−3, −9) (3, −9) (3, 9)
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By simple substitution on the left side and on the right side of the given equation, we have to
 For <span>coordinates (-3,-9)
 -9</span><span>=−8|-3+3|−9
 -9</span><span>=−8|0|−9
</span> -9=−9
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3 years ago
How to graph an exponential function
irina1246 [14]

Step-by-step explanation:

Exponential function is given by general form y=ab^x

Where a and b are constants.

say a=1 and b=2 then we can write function as :

y=1*2^x

or y=2^x

To graph this or any exponential function, we just need to find some points then join them by a curved line.

Like plug x=0, 1, 2,... into above function and find points:

plug x=1

y=2^x=2^1=2

Hence point is (1,2)

Find more points similarly then graph them to get the graph as shown below:


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3 years ago
X<br> Find the value<br> of x. Show<br> 3<br> 10<br> your work.
pickupchik [31]

Step-by-step explanation:

<em>Hello</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em><em>!</em>

<em>Let</em><em> </em><em>ABC</em><em> </em><em>be</em><em> </em><em>a Right angled triangle</em><em>, </em>

<em>where</em><em>,</em><em> </em><em>AB</em><em> </em><em>=</em><em> </em><em>3</em>

<em>BC</em><em>=</em><em> </em><em>1</em><em>0</em>

<em>and</em><em> </em><em>AC</em><em>=</em><em> </em><em>x</em>

<em>now</em><em>,</em>

<em>As</em><em> </em><em>the</em><em> </em><em>triangle</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>Right angled triangle</em><em>, </em><em>taking</em><em> </em><em>angle C</em><em> </em><em>as</em><em>refrence</em><em> </em><em>angle</em><em>.</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em> </em><em>h</em><em>=</em><em> </em><em>AC</em><em> </em><em>=</em><em> </em><em>x</em>

<em>p</em><em>=</em><em> </em><em>AB</em><em> </em><em>=</em><em> </em><em>3</em>

<em>b</em><em>=</em><em> </em><em>BC</em><em>=</em><em> </em><em>1</em><em>0</em>

<em>now</em><em>,</em><em> </em><em>by</em><em> </em><em>Pythagoras</em><em> </em><em>relation we get</em><em>, </em>

<em>h =    \sqrt{ {p}^{2} +  {b}^{2}  }</em>

<em>or ,\: h =  \sqrt{ {3}^{2}  +  {10}^{2} }</em>

<em>by</em><em> </em><em>simplifying it we get</em><em>, </em>

<em>h</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em><em>4</em><em>4</em><em>0</em><em>3</em><em>0</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em> </em><em>answer is</em><em> </em><em>x</em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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3 years ago
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