Answer:
One standard deviation above the mean means a z-score of 1.0. If we put this into the calculator as normalcdf(1,999) = .159
15.9 percent of the athletes would have a distance greater than 20.56 meters.
Now multiply the number of athletes by the percent.
.159 * 40 = 6.346 = about 6 athletes
c. about 6 athletes
Answer:
third option is the correct answer
go with the names of the triangle
the triangles are HIJ and LMN
so the ratios will be accordingly
Answer:
1.08 Miles
How I Found The Answer:
2.65 + 1.52 + 0.75 = 4.92
6 - 4.92 = 1.08
I Said Alexis Wished To Have An Even Number So She Ran 1.08 Miles.
Answer:
66.48% of full-term babies are between 19 and 21 inches long at birth
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean length of 20.5 inches and a standard deviation of 0.90 inches.
This means that 
What percentage of full-term babies are between 19 and 21 inches long at birth?
The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then
X = 21



has a p-value of 0.7123
X = 19



has a p-value of 0.0475
0.7123 - 0.0475 = 0.6648
0.6648*100% = 66.48%
66.48% of full-term babies are between 19 and 21 inches long at birth