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Vika [28.1K]
3 years ago
11

Solve for n. n+4+10=25 Enter your answer in the box. n= __

Mathematics
2 answers:
-BARSIC- [3]3 years ago
8 0

Answer:

11

Step-by-step explanation:

n+4+10=25

n+14=25

n+14=25

  -14  -14

n=11

KatRina [158]3 years ago
4 0
N = 11 that is the answer
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Lupita brought seven pounds of pretzels at a local wholesaler for 16.80 her friend Charles about 5 pounds of pretzels at the sup
Mashutka [201]

Answer:

Step-by-step explanation:

Lupita brought seven pounds of pretzels at a local wholesaler for 16.80. This means that the rate at which she bought one pound of pretzel at the local wholesaler would be

16.80 / 7 = $2.4 per pounds of pretzels

Her friend, Charles about 5 pounds of pretzels at the supermarket 12.75. This means that the rate at which Charles bought one pound of pretzel at the supermarket would be

12.75 / 5 = $2.55 per pounds of pretzels

Charles's reasoning is wrong because the rate at which he bought one pound of pretzel is higher than that of Lupita's

7 0
3 years ago
Susie drank 2 3 liter of water Monday before going jogging. She drank 3 4 liter of water after her jog. How much water did Susie
Naya [18.7K]
I’m assuming the numbers are 2/3 and 3/4 so find the common denominator. 2/3x4=8/12 and 3/4x3=9/12 so 8/12+9/12= 17/12 or 1 and 5/12
8 0
3 years ago
What if I replace-x with -3?<br> Y= -x +6
Sunny_sXe [5.5K]

Answer:

y=9

Step-by-step explanation:

replace the x only with -3

you get y = - -3 + 6

Two negatives= positive

+3+6=9

y=9

8 0
3 years ago
Read 2 more answers
Sansa solved the equation 1/2(8x-6)=x+9​
Gnom [1K]

Answer:

x=4

Step-by-step explanation:

;)

4 0
3 years ago
5. (6 marks) Use mathematical induction to prove that for each integer n ≥ 4, 5^n ≥ 2^2n+1 + 100.
Tju [1.3M]

Step-by-step explanation:

We will prove by mathematical induction that, for every natural n\geq 4,  

5^n\geq 2^{2n+1}+100

We will prove our base case, when n=4, to be true.

Base case:

5^4=625\geq 612=2^{2*4+1}+100

Inductive hypothesis:  

Given a natural n\geq 4,  

5^n\geq 2^{2n+1}+100

Now, we will assume the induction hypothesis and then use this assumption, involving n, to prove the statement for n + 1.

Inductive step:

2^{2(n+1)+1}+100=2^{2n+1+2}+100=\\=4*2^{2n+1}+100\leq 4(2^{2n+1}+100)\leq 4*5^n

With this we have proved our statement to be true for n+1.  

In conlusion, for every natural n\geq4.

5^n\geq 2^{2n+1}+100

7 0
3 years ago
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