RS => y - 5 = (8 - 5)/(1 - (-1)) (x - (-1))
y - 5 = 3/2 (x + 1) => slope = 3/2
ST => y - 8 = (-2 - 8)/(7 - 1) (x - 1)
y - 8 = -10/6 (x - 1) = -5/3 (x - 1) => slope = -5/3
TU => y - (-2) = (0 - (-2))/(2 - 7) (x - 7)
y + 2 = 2/5(x - 7) => slope = 2/5
UR => y = 5/(-1 - 2) (x - 2)
y = -5/3 (x - 2) => slope = -5/3
The median is the line joining the midpoints of the non-parallel sides.
Midpoint of RS = ((-1 + 1)/2, (5 + 8)/2) = (0, 13/2)
Midpoint of TU = ((7 + 2)/2, -2/2) = (9/2, -1)
Equation of the line joining (0, 13/2) and (9/2, -1) is given by y - 13/2 = (-1 - 13/2)/(9/2) x
y - 13/2 = (-15/2)/(9/2) x
y - 13/2 = -15/9x
18y - 117 = -30x
30x + 18y = 117
Answer:
The length of each red rod is 10 cm and the length of each blue rod is 14 cm
Step-by-step explanation:
Let
x ----> the length of each red rod in centimeters
y ----> the length of each blue rod in centimeters
we know that
----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is the point (10,14)
see the attached figure
therefore
The length of each red rod is 10 cm and the length of each blue rod is 14 cm
Answer:
<h2>36b + 60c</h2>
Step-by-step explanation:
Put a = 6 to the expression 2a(3b + 5c):
(2)(6)(3b + 5c) = 12(3b + 5c) <em>use the distributive property</em>
= (12)(3b) + (12)(5c) = 36b + 60c
Answer:
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Answer:
When we have 3 numbers, like:
a, b and c.
Such that:
a < b < c.
These numbers are a Pythagorean triplet if the sum of the squares of the two smaller numbers, is equal to the square of the larger number:
a^2 + b^2 = c^2
This is equivalent to the Pythagorean Theorem, where the sum of the squares of the cathetus is equal to the hypotenuse squared.
Now that we know this, we can check if the given sets are Pythagorean triples.
1) 3, 4, 5
Here we must have that:
3^2 + 4^2 = 5^2
solving the left side we get:
3^2 + 4^2 = 9 + 16 = 25
and the right side:
5^2 = 25
Then we have the same in both sides, this means that these are Pythagorean triples.
2) 8, 15, 17
We must have that:
8^2 + 15^2 = 17^2
Solving the left side we have:
8^2 + 15^2 = 64 + 225 = 289
And in the right side we have:
17^2 = 17*17 = 289
So again, we have the same result in both sides, which means that these numbers are Pythagorean triples
