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3 years ago

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Sloan has 6 gallons of milk. He uses 2/3 of it to make hot chocolate. Then he uses 1/2 of the milk he has left to male cookies.

How many gallons of milk does he have left after making hot chocolate and cookies

1 answer:

jasenka [17]3 years ago

8 0

D̥ͦo̥ͦ y̥ͦo̥ͦu̥ͦ k̥ͦn̥ͦo̥ͦw̥ͦ D̥ͦe̥ͦc̥ͦi̥ͦm̥ͦḁͦl̥ͦs̥ͦ I̥ͦN̥ͦ f̥ͦr̥ͦḁͦc̥ͦt̥ͦi̥ͦo̥ͦn̥ͦs̥ͦ?

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Geoff wants to make a 200 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with a 8% alcohol solution. What

Marina86 [1]

Answer:

Volume of 3% alcohol = 80 ml

Volume of 8% alcohol = 120 ml

Step-by-step explanation:

Final volume of 6% alcohol solution = 200 ml

Let the volume of 3% alcohol volume = a ml

Therefore, volume of 8% alcohol = (200 - a) ml

Equation for the given situation will be,

3a + 8(200 - a) = 6×200

3a + 1600 - 8a = 1200

1600 - 5a = 1200

5a = 400

a = 80 ml

Therefore, volume of 3% alcohol to be used = 80 ml

And volume of 8% alcohol to be used = (200 - 80) = 120 ml

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3 years ago

PLSSS HELP IMMEDIATELY!!! ILL GIVE BRAINIEST!!! (if u provide a link, i’m not giving u brainiest!)

Tems11 [23]

Answer: B. (2,1)

Step-by-step explanation:

its not c because if you look at R you see that it is going 4,3 not 3,4 because when you doing ratios on a number line it goes x-axis then y-axis next not y-axis then the x-axis.

It's not D because if you look at Q you see that it is going 3,5 not 5,3 because when you doing ratios on a number line it goes x-axis then y-axis next not y-axis then x-axis.

That's the same thing for A so your answer is b.

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3 years ago

Read 2 more answers

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of <em>X</em> is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

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Where is the graph to fill in

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3 years ago

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zlopas [31]

Answer:

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