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Triss [41]
3 years ago
7

Sloan has 6 gallons of milk. He uses 2/3 of it to make hot chocolate. Then he uses 1/2 of the milk he has left to male cookies.

How many gallons of milk does he have left after making hot chocolate and cookies
Mathematics
1 answer:
jasenka [17]3 years ago
8 0
D̥ͦo̥ͦ y̥ͦo̥ͦu̥ͦ k̥ͦn̥ͦo̥ͦw̥ͦ D̥ͦe̥ͦc̥ͦi̥ͦm̥ͦḁͦl̥ͦs̥ͦ I̥ͦN̥ͦ f̥ͦr̥ͦḁͦc̥ͦt̥ͦi̥ͦo̥ͦn̥ͦs̥ͦ?
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Write money amounts using a leading zero if necessary & with 2 decimal places (For example: 0.80 or 0.72 or 1.23)
goldenfox [79]

9514 1404 393

Answer:

  1. 63 mph
  2. 3 donut holes per kid
  3. $0.70 per pound
  4. $2.25 per km

Step-by-step explanation:

In this context, "per" and "for" mean "divided by."

  1. 630 mi/(10 h) = 63 mi/h
  2. (24 dh)/(8 kid) = 3 dh/kid
  3. $3.50/(5 lb) = $0.70 /lb
  4. $32/(14 2/9 km) = $32/(128/9 km) = $(9/4)/km = $2.25 /km
3 0
3 years ago
If the measure of angle 5 equals 102 degrees, then the measure of angle 8 equals what?
kiruha [24]
I hope this helps you

7 0
3 years ago
I need help, please​
tensa zangetsu [6.8K]

Answer:

C

Step-by-step explanation:

12^2 = 144, 9^2 = 81, and 15^2 = 225.

144 + 81 = 225, therefore a^2 + b^2 = c^2.

4 0
3 years ago
Read 2 more answers
Please help me answer this with the correct answer :)
Andru [333]

Answer:

A.

Step-by-step explanation:

Amber get $150 per week no matter wut and +$10 per tree sold so if she sells 5 trees she gets a total of $200

Jorge gets $25 per tree sold and an extra $75at the end of the week so 25(5)=125+75=200 so they both end up with $200 at the end of the week

4 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
3 years ago
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