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Mazyrski [523]
3 years ago
13

Find the derivative of f(x)=7 by the limit process

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0
f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h

If f(x)=7, then

f'(x)=\displaystyle\lim_{h\to0}\frac{7-7}h=0

which is what you expect from a constant function.
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Is this right? plz help me
olga55 [171]

Answer:

no its the 3rd one

Step-by-step explanation:

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The entrance for the amusement park is $40, visitors purchase additional $2
pashok25 [27]

Answer:

2 tickets because round

Step-by-step explanation:

make an equation: 100=40x+2 and solve

2.45 tickets so only two

40+40 =80

100-80=20

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5 0
3 years ago
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2,5-[0,2+(-3,7+5)-1,4]
ValentinkaMS [17]

2.5 - (0.2 + (3.7 + 5) - 1.4) \\  = 2.5 - (0.2 + 4.2 - 1.4) \\  = 2.5 - (4.4 - 1.4) \\  = 2.5 - 3 \\  =  - 0.5
7 0
3 years ago
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A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
A factory makes cars at a constant rate. The table shows the number of car’s made for different length’s of time. A manager draw
blagie [28]

Answer:

im not sure if this is right or not but i did the math and got 26

Step-by-step explanation:

8 0
3 years ago
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