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soldi70 [24.7K]
3 years ago
10

one positive number is 5 times another number. the difference between the two numbers is 764, find the numbers

Mathematics
1 answer:
damaskus [11]3 years ago
5 0
<h3><u>The first number, x, is equal to 955.</u></h3><h3><u>The second number, y, is equal to 191.</u></h3>

x = 5y

x - y = 764

Because we have a value for x, we can plug it into the second equation to solve for y.

5y - y = 764

Combine like terms.

4y = 764

Divide both sides by 4.

y = 191

Because we have a value for y, we can solve for x.

x = 5(191)

x = 955


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Solve for the variable: p − 4.8 (less than or = to sign) 6.
VashaNatasha [74]
P - 4.8 ≤ 6
p - 4.8 + 4.8 ≤ 6 + 4.8
p ≤ 10.8

3 0
3 years ago
What is the slope of a line perpendicular to the line whose equation is 5x - y = -7.
BARSIC [14]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

5x-y=-7\implies 5x-y+7=0 \\\\\\ \stackrel{\stackrel{m}{\downarrow }}{5} x+7=y\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so a line perpendicular to that one above will have a slope of

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{5\implies \cfrac{5}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{5}}}

3 0
2 years ago
I need help on this question!
Wittaler [7]
It C I think
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6 0
2 years ago
Convert the equation y= -4x + 2/3 into general form equation and find t the values of A,B and C.
alukav5142 [94]

Answer:

<em>Standard form: </em>12x+3y-2=0<em></em>

<em>A = 12, B = 3 and C = -2</em>

<em></em>

Step-by-step explanation:

Given:

The equation:

y= -4x + \dfrac{2}3

To find:

The standard form of given equation and find A, B and C.

Solution:

First of all, let us write the standard form of an equation.

Standard form of an equation is represented as:

Ax+By+C=0

A is the coefficient of x and can be positive or negative.

B is the coefficient of y and can be positive or negative.

C can also be positive or negative.

Now, let us consider the given equation:

y= -4x + \dfrac{2}3

Multiplying the whole equation with 3 first:

3 \times y= 3 \times -4x + 3 \times \dfrac{2}3\\\Rightarrow 3y=-12x+2

Now, let us take all the terms on one side:

\Rightarrow 3y+12x-2=0\\\Rightarrow 12x+3y-2=0

Now, let us compare with Ax+By+C=0.

So, <em>A = 12, B = 3 and C = -2</em>

6 0
3 years ago
Which statement is true about the equations –3x + 4y = 12 and x – y = 1?
Firlakuza [10]
-3x + 4y = 12
x - y = 1....x = y + 1

-3(y + 1) + 4y = 12
-3y - 3 + 4y = 12
-3y + 4y = 12 + 3
y = 15

x - y = 1
x - 15 = 1
x = 1 + 15
x = 16

one solution (16,15)

6 0
3 years ago
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