3 years ago

Can someone help me with 1. And 2.

Mathematics

1 answer:

Ainat [17]3 years ago

3 0

Answer:

65, 112

Step-by-step explanation:

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Answer:

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3 years ago

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The table shows the concentration of a reactant in the reaction mixture over a period of time.

saveliy_v [14]

<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: $2.0 \times 10^{-3}$ </h3>

<em><u>Solution:</u></em>

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$Average\ rate = \frac{ \triangle c }{\triangle t }$

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

$Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}$

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5 0

3 years ago

Cunato es 2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2++2+2

mixas84 [53]

Answer:

Step-by-step explanation:

There's 27 2's, so 27 * 2 = 54. Note that multiplication exists for a reason: to avoid expression's where there's an absurd number of +'s.

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3 years ago

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