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3 years ago

Billy has $3.00. Bubble gum costs $.30. He bought four pieces.

Mathematics

2 answers:

xenn [34]3 years ago

7 0

Answer:

$0.30 x 4= $1.20

$3.00 divided by $1.20= $1.80

Step-by-step explanation:

I hope this is what you were looking for

frosja888 [35]3 years ago

4 0

$.30 x 4 = $1.20. Hope it’s right

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Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.

Bas_tet [7]

Answer:

The function touches the damping factor

at x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

The x-intercept of f(x) is

at x= $n\pi$

Step-by-step explanation:

Given function is f(x)= $e^{-3x} sin(x)$ and damping factor as y= $e^{-3x}$ and y= $(-1)e^{-3x}$

To find when function touches the damping factor:

For f(x)= $e^{-3x} sin(x)$ and y= $e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=e^{-3x}$

$sin(x)=1$

x= $\frac{(4n-3)\pi}{2}$

For f(x)= $e^{-3x} sin(x)$ and y= $(-1)e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=(-1)e^{-3x}$

$sin(x)=(-1)$

x= $\frac{(4n-1)\pi}{2}$

Therefore, The function touches the damping factor x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

To find x-intercept of f(x):

For x-intercept, y=0

f(x)= $e^{-3x} sin(x)$

y= $e^{-3x} sin(x)$

$e^{-3x} sin(x)=0$

Hence, $e^{-3x}$ is always greater than zero.

Therefore, $sin(x)=0$

x= $n\pi$

Thus,

The x-intercept of f(x) is at x= $n\pi$

7 0

3 years ago

Look at the picture attached :)

Karolina [17]

I think it is B
Not sure

4 0

3 years ago

Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).

kirill115 [55]

Answer:

The Correct option is Last one $y=-4x-4$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

Step-by-step explanation:

Given:

$y=-4x-3$

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

$y=-4x-3$ ..........Given

Comparing with Slope-Intercept form,

$y=mx+c$

Where m =slope

We get

$Slope = m = -4$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

8 0

3 years ago

A person owes a debt of $10

AleksandrR [38]

So the person is out of pocket of $10.00

6 0

3 years ago

What is the equation in standard form for (0,3) and (7,0)

Luden [163]

Answer:

3x + 7y = 21

Step-by-step explanation:

We have value of two points (0,3) and (7,0)

First, let's find the slope of this line. The formula for slope is:

Change in y/Change in x or (y₂ - y₁)/(x₂-x₁)

Where x₁ = 0 x₂= 7 y₁ = 3 y₂ = 0

(y₂ - y₁)/(x₂-x₁)

= (0-3)/(7-0)

=-3/7

Now we can write the equation in point-slope form:

y-y₁ = m(x-x₁)

y - 3 = -3/7(x-0)

y-3=-3x/7

y=-3x/7 + 3

Now let's convert this to standard form, by making the y-intercept by itself:

Ax + By = C

y=-3x/7 + 3

Multiply through by 7

7(y) = 7(-3x/7) + 7(3)

7y = -3x + 21

3x + 7y = 21

3 0

3 years ago