Answer:
The absolute maximum is
and the absolute minimum value is 
Step-by-step explanation:
Differentiate of
both sides w.r.t.
,


Now take 



![\Rightarrow 1-2\sin ^2t =\sin t \quad \quad [\because \cos 2t = 1-2\sin ^2t]](https://tex.z-dn.net/?f=%5CRightarrow%201-2%5Csin%20%5E2t%20%3D%5Csin%20t%20%20%5Cquad%20%5Cquad%20%20%5B%5Cbecause%20%5Ccos%202t%20%3D%201-2%5Csin%20%5E2t%5D)






In the interval
, the answer to this problem is 
Now find the second derivative of
w.r.t.
,

![\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cleft%5Bf%27%27%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%20%7B%5Cpi%7D6%7D%3D-2%5Ctimes%20%5Cfrac%20%7B%5Csqrt%203%7D2-4%5Ctimes%20%5Cfrac%7B%5Csqrt%203%7D2%3D-3%5Csqrt%203)
Thus,
is maximum at
and minimum at 
![\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0](https://tex.z-dn.net/?f=%5Cleft%5Bf%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%20%7B%5Cpi%7D6%7D%3D2%5Ctimes%20%5Cfrac%20%7B%5Csqrt%203%7D2%2B%5Cfrac%7B%5Csqrt%203%7D2%3D%5Cfrac%7B3%5Csqrt%203%7D2%5C%3B%5Ctext%7Band%7D%5C%3B%5Cleft%5Bf%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%7B%5Cpi%7D2%7D%3D%202%5Ctimes%200%2B0%3D0)
Hence, the absolute maximum is
and the absolute minimum value is
.
Answer:
The solution to the system of linear equations is (1,9).
Step-by-step explanation:
The given system of linear equations
... (1)
.... (2)
Subtract equation (2) from equation (1) to eliminate y.
On combining like terms, we get
Add 8 on both sides.

Divide both sides by 8.

The value of x is 1.
Substitute x=1 in equation (1).



The value of y is 9.
Therefore the solution to the system of linear equations is (1,9).
Hi there! The answer is B.

First we work out the parenthesis, which is easy because we can just remove them.

Now rearrange our expression (in order to collect terms later).

Next up is collecting the terms.

The answer is B.
~ Hope this helps you!
Answer:
384 Square Inches
Step-by-step explanation:
Given a square pyramid with base side edge and slant height

In the given pyramid:
- Slant Height=20 inches
- Base Edge = 8 Inches
Therefore:
Area of Base, A =8 X 8 =64 Square Inches
Perimeter of base, p =4 X 8 =32 Inches
