<span />Answer:<span>k2+1</span>−1k=<span>−<span>2k</span></span>Also Plz give me a Thanks PLZ

We have, Discriminant formula for finding roots:

Here,
- x is the root of the equation.
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term
1) Given,
3x^2 - 2x - 1
Finding the discriminant,
➝ D = b^2 - 4ac
➝ D = (-2)^2 - 4 × 3 × (-1)
➝ D = 4 - (-12)
➝ D = 4 + 12
➝ D = 16
2) Solving by using Bhaskar formula,
❒ p(x) = x^2 + 5x + 6 = 0



So here,

❒ p(x) = x^2 + 2x + 1 = 0



So here,

❒ p(x) = x^2 - x - 20 = 0



So here,

❒ p(x) = x^2 - 3x - 4 = 0



So here,

<u>━━━━━━━━━━━━━━━━━━━━</u>
Answer:
Patricia spent $24 on presents, while Donald spent $12 and Carl spent $36.
Step-by-step explanation:
The problem is to solve how much money each person spent on presents in the year, through a series of equivalences. In order to determine how much money each one spent, the following equation must be proposed:
Patricia = X
Donald = 1 / 2X
Carl = 3/2 X
X + 1 / 2X + 3 / 2X = 72
1X + 0.5 X + 1.5 X = 72
3X = 72
X = 72/3
X = 24
Thus, Patricia spent $ 24 on presents, while Donald spent $ 12 (2/24) and Carl spent $ 36 (1.5 x 24).
Answer:
The height of this rectangle is 8/10
Step-by-step explanation:
Please see attachment .
<h2>For this example I am going to use Cape Coral-Fort Myers Florida which was the fastest growing city of 2017.
</h2><h2>As of January of 2000, the population of the city was 102,286, and as of January 1 of 2010, the population was 154,305; therefore, I'm going to examine a population growth over a period of 10 years.
</h2><h2>I am going to use the standard model for population growth:
</h2><h2>
</h2><h2>Where:
</h2><h2>= time (in years)
</h2><h2>= growth rate
</h2><h2>= initial population </h2><h2>= population after a time </h2><h2>
</h2><h2>Now, I'm going to replace the values in the equation to get :
</h2><h2>
</h2><h2>
</h2><h2>
</h2><h2>
</h2><h2>
</h2><h2>
</h2><h2>Finally, I will multiply x by 100% to obtain 4% which the growing rate of Cape Coral-Fort Myers from 2000 to 2010.</h2>