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dsp73
2 years ago
15

Help and ill give brainliest

Mathematics
2 answers:
Zarrin [17]2 years ago
6 0

Answer:

C. 3 a ^2 b^11 /2

Step-by-step explanation:

Karo-lina-s [1.5K]2 years ago
6 0

Answer:

i hope this helps

Step-by-step explanation:

c

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Help me please!!!!!!!!!!!!
goldenfox [79]

Answer: I think it's no, sorry if I can't help

Step-by-step explanation:

6 0
3 years ago
Exponential Growth and Decay The expressions below represent either exponential growth or exponential decay. Check all the expre
Tomtit [17]

Answer:

First one: 5x3(0.75)2t

and fourth one: 0.05x500(0.005)t

Step-by-step explanation:

In order to have an exponencial decay, the rate of the exponencial function needs to be lesser than 1.

The rate is the value between parenthesis, so in the first equation, the rate is 0.75, so this is an exponencial decay.

The second equation has rate = 2.4, so this is not an exponencial decay.

The third equation has rate = 1.04, so this is not an exponencial decay.

The fourth equation has rate = 0.005, so this is an exponencial decay.

5 0
3 years ago
Read 2 more answers
Can u guys help i need to make this longer lol
Marizza181 [45]
I don’t under stand the question. What do you want me to answer
5 0
3 years ago
\large -6x+6y=6<br> \large 6x+3y=12
Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1)  = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0
3 years ago
Factor completly 4x^2 +8x -5
DaniilM [7]

∑ Hey, jillianwagler ⊃

Answer:

\left(2x-1\right)\left(2x+5\right)

Step-by-step explanation:

<u><em>║Given info║:</em></u>

<em>Factor completely: </em>4x^2 +8x -5

<u><em>Solution~:</em></u>

<em>Breaking the expression~:  </em>\left(4x^2-2x\right)+\left(10x-5\right)

<em>Factor out 2x from 4x² -2x : 2x(2x-1)</em>

<em>Factor out 5 from 10x - 5 : 5(2x - 1)</em>

<em>Put together: </em>=2x\left(2x-1\right)+5\left(2x-1\right)

Factor out 2x - 1: =\left(2x-1\right)\left(2x+5\right)

<u><em>xcookiex12</em></u>

<em>8/19/2022</em>

4 0
2 years ago
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