Answer:
<h2>C) (negative 1, one-half), (0, 1), (1, 2), (2, 4)</h2>
Step-by-step explanation:
The set C could be generated by an exponential function. The main reason is that exponential functions hava a restricted range, it can't have negative numbers or the number zero, because power can only be equal or greater than 1.
Additionally, for all exponentials, a null exponent gives 1 as an answer, so point (0, 1) is always present in an exponential function.
Therefore, the right answer is C.
Answer:
1. 2(k + 3)
2. 3. 75 + k
Step-by-step explanation:
1. 2x + 6
Since, 2 is a common factor of 2 and 6, we can take that common outside.
So, 2x + 6 = 2(x + 3)
Note that in the initial expression, this 2 was distributed to arrive at 2x + 6.
2. (1.5 + k) + 2.25
This is simple addition. We can simply remove the brackets to have:
1.5 + k + 2.25
Since, the like terms can be added, we will have:
1.5 + 2. 25 + k
= 3. 75 + k
Three of the four towns are on the vertices of the triangle ΔCBD, through
which the bearing can calculated.
<h3>Response:</h3>
- The bearing of D from B is approximately <u>209.05°</u>
<h3>Method by which the bearing is found;</h3>
From the given information, we have;
AC = AB = 25 km
∠BAC = 90° (definition of angle between north and east)
ΔABC = An isosceles right triangle (definition)
∠ACD = ∠ABC = 45° (base angles of an isosceles right triangle)
The bearing of <em>D</em> from <em>B</em> is the angle measured from the north of <em>B</em> to the
direction of <em>D.</em>
<em />
Therefore;
- The bearing of D from B ≈ 90° + (180° - 60.945°) = <u>209.05°</u>
Learn more about bearings in mathematics here:
brainly.com/question/10710413
Answer:
9-3=6
Step-by-step explanation:
Line from left to right: number 9 (absolute value)
Line from right to left: number 3 (absolute value)
Overall: 9-3=6
We used the minus sign for 3 because the corresponding line is oriented in the opposite direction.
Answer:
We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on. We say that f(x) has a relative (or local) minimum at x=c iff(x)≥f(c) f ( x ) ≥ f ( c ) for every x in some open interval around x=c .
