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andreev551 [17]
3 years ago
15

Please help solve these equations! Show steps(: thank you

Mathematics
1 answer:
Bond [772]3 years ago
6 0
Y= x^2-58
X^2-58=0
X^2=58
X= sqrt of 58
X= 7.6

Y= x^2+13
X^2+13=0
X^2=-13
Get sq rt of 13 the negative becomes i
X= 3.6i

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Hello LovingAngel!

To find the slope, you can use the formulas \frac{rise}{run} as well as \frac{y^2-y^1}{x^2 - x^1}. I am using the latter to calculate and ensuring my answer with the former. 

[Note: (x,y) is the format for ordered pairs]

First pair:  value 1:(1,5) and value 2:(2,8) 
\frac{y^2-y^1}{x^2 - x^1} -> \frac{8 - 5}{2 - 1} -> \frac{3}{1} or 3. 

The slope for (1,5) and (2,8) is 3(/1). 

Second pair: value 1: (3,1) value 2 (3,-1)

\frac{y^2-y^1}{x^2 - x^1} -> \frac{-1 - 1}{3 - 3} -> \frac{-2}{0}
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Checking work with \frac{rise}{run}
1. Slope: 3/1, meaning rise (y) +3 and run (x) +1.  (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) <span>✔</span>

6 0
3 years ago
At a coffee shop, the first 100 customers'
Rudiy27

Answer:

so there is a 5% change of or ordering a large cold drink

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

4 0
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