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andreev551 [17]
3 years ago
15

Please help solve these equations! Show steps(: thank you

Mathematics
1 answer:
Bond [772]3 years ago
6 0
Y= x^2-58
X^2-58=0
X^2=58
X= sqrt of 58
X= 7.6

Y= x^2+13
X^2+13=0
X^2=-13
Get sq rt of 13 the negative becomes i
X= 3.6i

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Solve for x<br> Urgent need help
fiasKO [112]
I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± <span>√ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 </span>± <span>√13^2 - 4(2)(-24) / 2(2)
x= -13 </span><span>± √169 - 8 (-24) / 4</span>
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So you have: -13 </span><span>± 19 / 4.
Here's where you take the equation </span>-13 <span>± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
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Now all is left to do is divide the two numbers by 4.
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x = -8, 3/2</span>
6 0
4 years ago
What value of x is in the solution set of 9(2x + 1) &lt; 9x – 18?
fredd [130]
To solve these kinds of problems, it is necessary to isolate x:

9(2x + 1) <span>< 9x - 18

Distribute 9:
18x + 9 </span><span>< 9x - 18

Subtracting 9 from both sides of the equation:
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Subtracting 9x from both sides of the equation:
18x - 9x </span><span>< 9x - 27 - 9x
9x </span><span>< -27

x </span><span>< -3

Therefore, values of x </span><span>< -3 will satisfy the given equation.</span>
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What is the following product? 3 root 5 times root 2
Crazy boy [7]

\bf \textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt[3]{5}\cdot \sqrt{2}\implies \sqrt[3]{5^1}\cdot \sqrt[2]{2^1}\implies 5^{\frac{1}{3}}\cdot 2^{\frac{1}{2}}\implies 5^{\frac{2}{6}}\cdot 2^{\frac{3}{6}}\implies \sqrt[6]{5^2}\cdot \sqrt[6]{2^3} \\\\\\ \sqrt[6]{25}\cdot \sqrt[6]{8}\implies \sqrt[6]{25\cdot 8}\implies \sqrt[6]{200}

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Step-by-step explanation:

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