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andreev551 [17]
3 years ago
15

Please help solve these equations! Show steps(: thank you

Mathematics
1 answer:
Bond [772]3 years ago
6 0
Y= x^2-58
X^2-58=0
X^2=58
X= sqrt of 58
X= 7.6

Y= x^2+13
X^2+13=0
X^2=-13
Get sq rt of 13 the negative becomes i
X= 3.6i

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1. Given

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2 years ago
. A triangle has side lengths of 8, 7, and 14. To the nearest tenth of a degree find the measure of the angle opposite the side
4vir4ik [10]

Given:

The measure of three sides of a triangle are 8, 7 and 14.

To find:

The measure of the angle opposite the side of length 8.

Solution:

According to the Law of Cosine:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Let a=8, b=7 and c=14, then by using Law of Cosine, we get

\cos A=\dfrac{7^2+14^2-8^2}{2(7)(14)}

\cos A=\dfrac{49+196-64}{196}

\cos A=\dfrac{181}{196}

Taking cos inverse on both sides.

A=\cos^{-1}\dfrac{181}{196}

A=22.561328

A\approx 22.6

Therefore, the measure of the angle opposite the side of length 8 is 22.6 degrees.

7 0
3 years ago
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Volgvan
The stack of cards are 1 inch tall all together taking up 8 inch’s (cubed)or half of the space
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Find the product of (−x−3)(2x2+5x+8)
Dmitrij [34]
The product is -5x^2-27x-36
8 0
2 years ago
Read 2 more answers
. a) In a group of 75 students, 20 liked football only, 30 liked cricket only and 18 did not like any of two games? (i) How many
qaws [65]

i)50

<u>Steps</u>

30+20=50

ii)7

<u>Steps</u>

75-(30+20)-18

=75-(50)-18

=7

iii)20

<u>Steps</u>

From the available data from the question

iv)30

<u>Steps</u>

From the available data from the questionl

v)From the attcged image file

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