Question

Someone help me with these two. I'll give you brainliest and 25 points!! MATHEMATICIANS OUT THERE HELP

Answer 1

Hello LovingAngel!

To find the slope, you can use the formulas $\frac{rise}{run}$ as well as $\frac{y^2-y^1}{x^2 - x^1}$. I am using the latter to calculate and ensuring my answer with the former. 

[Note: (x,y) is the format for ordered pairs]

First pair:  value 1:(1,5) and value 2:(2,8) 
$\frac{y^2-y^1}{x^2 - x^1}$ -> $\frac{8 - 5}{2 - 1}$ -> $\frac{3}{1}$ or 3. 

The slope for (1,5) and (2,8) is 3(/1). 

Second pair: value 1: (3,1) value 2 (3,-1)

$\frac{y^2-y^1}{x^2 - x^1}$ -> $\frac{-1 - 1}{3 - 3}$ -> $\frac{-2}{0}$
Slope for the second pair is -2/0

Checking work with $\frac{rise}{run}$
1. Slope: 3/1, meaning rise (y) +3 and run (x) +1.  (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) ✔