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VikaD [51]
3 years ago
15

What is 32.5% of 38.4?

Mathematics
1 answer:
torisob [31]3 years ago
7 0
Hey there, 
100% = 38.4
1% = 38.4 / 100
      = 0.384
32.5% = 0.384 x 32.5
           = 12.48
Thus, 12.48  is 32.5% of 38.4

Hope this helps :))

~Top
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Answer:

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Step-by-step explanation:

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To answer this question, we can assume some different possibilities for the answer, since it is incomplete (or with not clear options):

a. \\ \frac{PMT}{r}

b. \\ PMT*\frac{(1+r)^{n}-1}{r}*(1 + r)

c. \\ PMT*\frac{(1+r)^{n} - 1}{r}  

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Step-by-step explanation:

The present value of a <em>perpetuity</em> is an <em>amount of money needed to invest today</em> to have a perpetuity, or an annuity paid for life, considering an interest rate of <em>r</em>.

PMT is a finance term for <em>payment</em> and <em>r </em>is the interest rate (roughly, an important quantity that defines how much it can be obtained for an investment).

In general, the present value can be mathematically defined as:

\\ PV(r) = \frac{PMT_{0}}{(1+r)^{0}} + \frac{PMT_{1}}{(1+r)^{1}} + \frac{PMT_{2}}{(1+r)^{2}}+\dotsc+\frac{PMT_{n}}{(1+r)^{n}}

Where <em>n</em> represents the number of periods for the investment.

On the other hand, an annuity, given a present value <em>PV</em>, is defined by:

\\ PMT= A = PV*(1+r)^{n}*(\frac{r}{(1+r)^{n}-1})

Solving this equation for <em>PV</em> (present value) to define the present value of an annuity, we have:

\\ PV = \frac{(1+r)^{n}-1}{(r*(1+r)^{n})}*PMT

But the question is asking for an annuity paid for life (theoretically, for infinite periods of time); then, if we calculate the <em>limit</em> for the previous equation when <em>n</em> tends to <em>infinity</em>, we find that:

\\ lim_{n\to\infty} \frac{(1+r)^{n}-1}{(r*(1+r)^{n})}*PMT

\\ (lim_{n\to\infty} \frac{(1+r)^{n}}{r*(1+r)^{n}} - lim_{n\to\infty} \frac{1}{r*(1+r)^{n}})*PMT

\\ (lim_{n\to\infty} \frac{(1+r)^{n}}{(1+r)^{n}}*\frac{1}{r} - lim_{n\to\infty} \frac{1}{r*(1+r)^{n}})*PMT

\\ (lim_{n\to\infty} 1*\frac{1}{r} - lim_{n\to\infty} \frac{1}{r*(1+r)^{n}})*PMT

The second term of the previous expression tends to 0 (zero) when <em>n</em> tends to <em>infinity</em>, then:

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