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miv72 [106K]
4 years ago
14

A poll of 1,068 adult Americans reveals that 48% of the voters surveyed prefer the Democratic candidate for the presidency. At t

he 0.01 level of significance, test the claim that at least half of all voters prefer the Democrat.
State the Test Statistics.
Mathematics
1 answer:
Alik [6]4 years ago
7 0

Answer: We will not accept the null hypothesis.

Step-by-step explanation:

Since we have given that

sample size n = 1068

\hat{p} = 48% = 0.48

At 0.01 level of significance, z = - 2.58

Hypothesis are:

H_0:p=0.5\\\\H_a:p\neq 0.5

So, test statistic value would be:

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.48-0.50}{\sqrt{\dfrac{0.5\times 0.5}{1068}}}\\\\z=\dfrac{-0.02}{0.0152}\\\\z=-1.315

So, test statistic > critical value.

Hence, we will not accept the null hypothesis.

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We are asked to find 7 is what percent to 30.

We will use proportions to solve our given problem.      

Let us assume that 7 is n% of 30. So we can set a proportion as:

\frac{n}{100}=\frac{7}{30}

Let us solve for n.

\frac{n}{100}\cdot 100=\frac{7}{30}\cdot 100

n=\frac{7}{3}\cdot 10

n=\frac{70}{3}

n=23.333

Therefore, 7 is 23.333\% of 30.

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PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab
Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

m=\frac{y_2-y_1}{x_2-x_1}

The product of slopes of two perpendicular lines is -1.

Slope of GR is

\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}

Slope of RT is

\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1

Product of slopes of GR and RT is

\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

(x,y)\rightarrow(x-1,y-2)

Then the coordinates of T' are

(2,6)\rightarrow(2-1,6-2)

(2,6)\rightarrow(1,4)

Slope of RT' is

\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}

Product of slopes of GR and RT' is

\frac{-4}{3}\times \frac{3}{4}=-1

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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