Answer:
Part 1
Type II error
Part 2
No ; is not ; true
Step-by-step explanation:
Data provided in the question
Mean = 100
The Random sample is taken = 43 students
Based on the given information, the conclusion is as follows
Part 1
Since it is mentioned that the classes are successful which is same treated as a null rejection and at the same time it also accepts the alternate hypothesis
Based on this, it is a failure to deny or reject the false null that represents type II error
Part 2
And if the classes are not successful so we can make successful by making type I error and at the same time type II error is not possible
Therefore no type II error is not possible and when the null hypothesis is true the classes are not successful
Answer:
P = 328 yards
Step-by-step explanation:
formula is P= 2l + 2w
Answer: Choice B
There is not convincing evidence because the interval contains 0.
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Explanation:
The confidence interval is (-0.29, 0.09)
This is the same as writing -0.29 < p1-p1 < 0.09
The thing we're trying to estimate (p1-p2) is between -0.29 and 0.09
Because 0 is in this interval, it is possible that p1-p1 = 0 which leads to p1 = p2.
Therefore, it is possible that the population proportions are the same.
The question asks " is there convincing evidence of a difference in the true proportions", so the answer to this is "no, there isn't convincing evidence". We would need both endpoints of the confidence interval to either be positive together, or be negative together, for us to have convincing evidence that the population proportions are different.
202 because you can round it to 200
Answer:
.903089987
Step-by-step explanation:
