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abruzzese [7]
2 years ago
15

Which of the following inequalities matches the graph?

Mathematics
1 answer:
S_A_V [24]2 years ago
7 0
X<-3 would be the answer
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Find the value of the expression |2x−8| where x=−2.5; 0; 4; 5; 9.5.
Lelu [443]

The absolute value |x| returns the "positive version" of a number. In other words, if x is already positive, then |x|=x. Otherwise, if x is negative, then the absolute value changes its sign, so that it returns positive: |x|=-x.

So, in this case, we have to plug the required values for x in the expression 2x-8. Then, if the result is positive we're ok, otherwise we discard the negative sign.

We have:

x=-2.5 \implies |2x-8| = |-5-8|=|-13|=13

x=0 \implies |2x-8| = |0-8|=|-8|=8

x=4 \implies |2x-8| = |8-8|=|0|=0

x=5 \implies |2x-8| = |10-8|=|2|=2

x=9.5 \implies |2x-8| = |19-8|=|11|=11

5 0
3 years ago
PLEASE HELP! Math (recursive sequences)
stira [4]

Answer:

a₄ = 123

Step-by-step explanation:

a₁ = 1

a₂ = (1)² + 2

a₂ = 3

a₃ = (3)² + 2

a₃ = 11

a₄ = (11)² + 2

a₄ = 123

6 0
3 years ago
When she graduates college, linda will owe $43,000
Ad libitum [116K]

Answer:

Good For Her

Step-by-step explanation:

She is now in debt of 43,000 and she will now be poor

3 0
3 years ago
Use three fours to make 11.
mr Goodwill [35]
4 + 4 + 4 - 1 = 11? Was it supposed to be an equation? I am confused.
7 0
3 years ago
A manufacturer is designing a flashlight. For the flashlight to emit a focused beam, the bulb needs to be on the central axis of
aalyn [17]
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12

Source:
http://www.1728.org/quadr4.htm




5 0
3 years ago
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