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Nina [5.8K]
3 years ago
11

X=3y + 1 2x + 4y =12

Mathematics
1 answer:
Alika [10]3 years ago
4 0

Answer:

the solution is (4, 1).

Step-by-step explanation:

The goal here is to "solve this system of linear equations."  You need to share that along with the equations.

We can begin the solution by substituting 3y + 1 for x in the second equation:

2(3y + 1) + 4y = 12

Performing the multiplication, we get 6y + 2 + 4y = 12, or 10y = 10.

Then y must be 1.

Substituting 1 for y in the first equation, we get x = 3(1) + 1 = 4

Thus, the solution is (4, 1).

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B. 6x^{2}+6y^{2}=144

Step-by-step explanation:

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WHAT IS THE SUM OF 76/81 X 80/76
Advocard [28]

Answer:

80/81

Step-by-step explanation:

hope this helps!

6 0
2 years ago
Read 2 more answers
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
PLEASE HELP I NEED A ASNSWER ASAP
stiks02 [169]
7 yes is a function
8 is not a function
7 0
3 years ago
What’s the answer ????
Temka [501]

Answer:

Answer is 4/25

Step-by-step explanation:

0.16*100 = 16 which would allow us to say 16/100

now you can divide 16 and 100 by 4 which would be

16/4 = 4 and 100/4= 25

therefore the answer is 4/25

8 0
3 years ago
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