This sequence be represented as a recursive equation by a1=8 and an=2a1
<u>Step-by-step explanation</u>:
- 'Recursive' refers to the repetition of a specific process in a sequence.
- The given sequence is {8,16,32,64}.
- If the value is 2 times the previous value, then an=2a(n-1)
Let a1=8,
then a2 = 2a(2-1)
⇒ a2 = 2a1
⇒ a2 = 2(8)
⇒ a2 = 16
Similarly,
For a2=16,
⇒ a3 = 2(a2)
⇒ a3 = 2(16)
⇒ a3 = 32
For a3=32,
⇒ a4 = 2(a3)
⇒ a4 = 2(32)
⇒ a4 = 64
∴ The equation is recursive as a1=8 and an=2a1 to follow the sequence.
Answer:
square root of 26 (sorry couldn't get the symbol)
Step-by-step explanation:
C^2 = A^2 + B^2 (Pythagoras Theorem)
C^2 = 5^2 + 1^2
C^2 = 26
take square root of both sides
C =
Answer:
32+33+34
Step-by-step explanation:
If I understand the question correctly, you're looking for 3 different numbers that are all consecutive that add up to be 99. The way I did it was finding 3 consecutive numbers that add to 9. 2, 3, 4. I knew the 10s place had to be a 3 because 30+30+30=90, 2+3+4=9, 90+9=99
If by description you mean simplification then: 84x/28
Step-by-step explanation:
the picture includes the answer and work
I plugged in 2 for x
the equations that got the same answer, I put together
