We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:
Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:
5^2 = 3^2 + x^2
x = 4
The radius is 4 + 1 cm = 5 cm
So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2
A = 25pi cm^2
To solve for the area of the shaded region:
Ashaded = Acircle - Atriangles
we need to solve for the area of the triangles:
A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2
Atriangles = 2 * 15
Atriangles = 30 cm^2
Ashaded = 25pi - 30
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Answer:
G = 1
h = 2
Step-by-step explanation:
4(2h - 3) - 5h = -6
8h - 12 - 5h = -6
3h - 12 = -6
3h = 6
h = 2
g = 2(2) - 3
g = 4 - 3
g = 1
Answer:
slope = 1/3
y-intercept = ( 0 , 2 )
equation :
y = 1/3x + 2
Step-by-step explanation:
Answer:
6.20%
Step-by-step explanation:
Missing question and graph attached.
Given: Total number of sample collected for female between age 20-29 is 548.
34 females that weighed over 250 pounds.
Now, finding percentage of females aged 20 to 29 weighed over 250 pounds.
Percent of Female over 250 pound aged 20-29= ![\frac{Number\ of \ females\ over\ 250\ pounds}{Total\ number\ of\ females\ aged 20-29} \times 100](https://tex.z-dn.net/?f=%5Cfrac%7BNumber%5C%20of%20%5C%20females%5C%20over%5C%20250%5C%20pounds%7D%7BTotal%5C%20number%5C%20of%5C%20females%5C%20aged%2020-29%7D%20%5Ctimes%20100)
⇒Percent of Female over 250 pound aged 20-29= ![\frac{34}{548} \times 100](https://tex.z-dn.net/?f=%5Cfrac%7B34%7D%7B548%7D%20%5Ctimes%20100)
⇒ Percent of Female over 250 pound aged 20-29= ![0.0620437\times 100](https://tex.z-dn.net/?f=0.0620437%5Ctimes%20100)
∴ Percent of Female over 250 pound aged 20-29= ![6.20437 \approx 6.20\%](https://tex.z-dn.net/?f=6.20437%20%5Capprox%206.20%5C%25)
Hence, 6.20% of females aged 20 to 29 weighed over 250 pounds.