The answer is A = P²/16

The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s = s²

Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.

Step 1:
P = 4s
s = P/4

Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16

4 0

3 years ago

Use the drawing tool(s) to form the correct answer on the provided coordinate plane.

vlada-n [284]

Answer:

Step-by-step explanation:

X^2-6x+5=x^2-5x-x+5=x(x-5)-(x-5)=(x-5)(x-1)

Then we have (x-5)(x-1)=0 if x=5 or x=1.

Intersections on x are points (1,0) and (5,0), middle is (3,0).

Intersection with y is when put x=0 in equation, so you will get y=0-6*0+5, y=5. The point is (0,5).

From picture symmetry is line x=3.