The area of a regular hexagon with an apothem 18.5 inches long and a side 21 inches is 1, 165. 5 In²
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How to calculate the area of a regular hexagon</h3>
The formula is given thus;
Area of hexagon = (1/2) × a × P
where a = the length of the apothem
P = perimeter of the hexagon
Given a = 18. 5 inches
Note that Perimeter, p = 6a with 'a' as side
p = 6 × 21 = 126 inches
Substitute values into the formula
Area, A = 1 ÷2 × 18. 5 × 126 = 1 ÷2 × 2331 = 1, 165. 5 In²
Thus, the area of the regular hexagon is 1, 165. 5 In²
Learn more about the area of a hexagon here:
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Hello, I hope this helped and that I was right, have a nice day.
Hi I couldn’t do the work for the surface area on the picture because I didn’t have space left so here it is,
Formula: 2(lw+lh+wh)
Shape 1
(2.4 x 1.1) + (2.4 x1.8) + (1.1 x 1.8)= 8.94
8.94 x 2= 17.88
Shape 2
(2.4 x 1.1) + (2.4 x 0.5) + (1.1 x 0.5) = 4.39
4.39 x2 = 8.78
17.88+ 8.78
Answer:
c)
Step-by-step explanation:
x^2+4x-32 = (x-4)(x+8)
hence,
(x-4)(x+8) = 0
x = 4 or x = -8
the graph intersects at 4 not -4
Answer:
a11 = -53
Step-by-step explanation:
an = -6n +13
We want the 11th term, so n =11
a11 = -6(11) +13
= -66 +13
= -53